Sys.Argv[1], Indexerror: List Index Out of Range

sys.argv[1], IndexError: list index out of range

sys.argv represents the command line options you execute a script with.

sys.argv[0] is the name of the script you are running. All additional options are contained in sys.argv[1:].

You are attempting to open a file that uses sys.argv[1] (the first argument) as what looks to be the directory.

Try running something like this:

python ConcatenateFiles.py /tmp

IndexError: list index out of range: sys.argv[1] out of range

sys.argv[1] This code expects first command line argument. If that's missing then you will encounter this error.
Example:

some_script.py

import sys
sys.argv[1]

If you dont provide myfirst_agr(as shown below) then it will throw Index error what you are seeing.

some_script.py myfirst_agr

More examples are here

image_url = sys.argv[1] IndexError: list index out of range

sys.argv list is populated from the command line arguments passed to the script, so in case none are provided it's expected to get an error like

Traceback (most recent call last):
File "demo4.py", line 6, in <module>
image_url = sys.argv[1]
IndexError: list index out of range

An easy repro is to put

import sys
print(sys.argv[1])

in demo.py and run it using python demo.py. You'll get the output

$ python demo.py
Traceback (most recent call last):
File "demo.py", line 2, in <module>
print(sys.argv[1])
IndexError: list index out of range

but if you pass an argument to it using python demo.py foo you'll get the desired output:

$ python demo.py foo
foo

Specifically for your example, looks like when calling demo4.py script you're not passing image url command line argument. You can pass it using python demo4.py <image_url_goes_here>.

Python argv IndexError: list index out of range

The reason for the error is because args only has one element, the script name, not two. If you are trying to access the script name, use args[0].

I got an IndexError: list index out of range in sys.argv[1]

It looks like the program is expecting 2 float command line arguments.
`

k1  = float(sys.argv[1])   # starting value of K
k2 = float(sys.argv[2])

`

So you shuld probably launch it with something like

python main.py 100 200

To go more into detail, your code is reading command line arguments and it's expecting there to be 2 of them, that can also be parsed into float values.
Normally, the first command line argument is the script file itself, so sys.argv is always at least one element long.

That being said, you can either do as suggested above, and pass 2 floats as arguments, when launching the script, or just edit the script and hardcode 2 values instead of the ones read from the command line, like so

k1  = 100  
k2 = 200


Related Topics



Leave a reply



Submit