Splitting a String by List of Indices

Splitting a string by list of indices

s = 'long string that I want to split up'
indices = [0,5,12,17]
parts = [s[i:j] for i,j in zip(indices, indices[1:]+[None])]

returns

['long ', 'string ', 'that ', 'I want to split up']

which you can print using:

print '\n'.join(parts)

Another possibility (without copying indices) would be:

s = 'long string that I want to split up'
indices = [0,5,12,17]
indices.append(None)
parts = [s[indices[i]:indices[i+1]] for i in xrange(len(indices)-1)]

How to split string by list of Indexes python?

Here's a version using a list comprehension:

In [42]: s = "Hello there!"

In [43]: [s[v1:v2] for v1, v2 in zip([0]+l, l+[None])]
Out[43]: ['He', 'llo ', 'the', 're!']

Split python string by predifned indices

Like this?

>>> map(lambda x: test_string[slice(*x)], zip(split_points, split_points[1:]+[None]))
['the', 'quick', 'brown', 'fox', 'jumps', 'over', 'the', 'lazy', 'dog']

We're ziping split_points with a shifted self, to create a list of all consecutive pairs of slice indexes, like [(0,3), (3,8), ...]. We need to add the last slice (32,None) manually, since zip terminates when the shortest sequence is exhausted.

Then we map over that list a simple lambda slicer. Note the slice(*x) which creates a slice object, e.g. slice(0, 3, None) which we can use to slice the sequence (string) with standard the item getter (__getslice__ in Python 2).

A little bit more Pythonic implementation could use a list comprehension instead of map+lambda:

>>> [test_string[i:j] for i,j in zip(split_points, split_points[1:] + [None])]
['the', 'quick', 'brown', 'fox', 'jumps', 'over', 'the', 'lazy', 'dog']

How to split a python string based on indices?

i think something like this is what you are looking for

line = "I would like a hamburger"
lst = line.split()
for index, word in enumerate(lst):
    print(lst[index-2:index],lst[index+1:index+3])

Split a list into sub-lists based on index ranges

Note that you can use a variable in a slice:

l = ['a',' b',' c',' d',' e']
c_index = l.index("c")
l2 = l[:c_index]

This would put the first two entries of l in l2

String split with indices in Python

I think it's more natural to return the start and end of the corresponding splices. eg (0, 4) instead of (0, 3)

>>> from itertools import groupby
>>> def splitWithIndices(s, c=' '):
...  p = 0
...  for k, g in groupby(s, lambda x:x==c):
...   q = p + sum(1 for i in g)
...   if not k:
...    yield p, q # or p, q-1 if you are really sure you want that
...   p = q
...
>>> a = "This is a sentence"
>>> list(splitWithIndices(a))
[(0, 4), (5, 7), (8, 9), (10, 18)]

>>> a[0:4]
'This'
>>> a[5:7]
'is'
>>> a[8:9]
'a'
>>> a[10:18]
'sentence'

how to split string by multi lengths?

Try this:

def split(s, len_arr):
    res = []
    start = 0
    for part_len in len_arr:
        res.append(s[start:start+part_len])
        start += part_len
    return res

> split("294216673539910447", [3, 2, 3, 3, 2, 2, 3])
> ['294', '21', '667', '353', '99', '10', '447']

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