Range Over Character in Python

Alphabet range in Python

>>> import string
>>> string.ascii_lowercase
'abcdefghijklmnopqrstuvwxyz'
>>> list(string.ascii_lowercase)
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

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Alternatively, using range:

>>> list(map(chr, range(97, 123)))
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

Or equivalently:

>>> list(map(chr, range(ord('a'), ord('z')+1)))
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

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Other helpful string module features:

>>> help(string)
....
DATA
    ascii_letters = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
    ascii_lowercase = 'abcdefghijklmnopqrstuvwxyz'
    ascii_uppercase = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
    digits = '0123456789'
    hexdigits = '0123456789abcdefABCDEF'
    octdigits = '01234567'
    printable = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~ \t\n\r\x0b\x0c'
    punctuation = '!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~'
    whitespace = ' \t\n\r\x0b\x0c'

Python: how to print range a-z?

>>> import string
>>> string.ascii_lowercase[:14]
'abcdefghijklmn'
>>> string.ascii_lowercase[:14:2]
'acegikm'

To do the urls, you could use something like this

[i + j for i, j in zip(list_of_urls, string.ascii_lowercase[:14])]

Iterating each character in a string using Python

As Johannes pointed out,

for c in "string":
    #do something with c

You can iterate pretty much anything in python using the for loop construct,

for example, open("file.txt") returns a file object (and opens the file), iterating over it iterates over lines in that file

with open(filename) as f:
    for line in f:
        # do something with line

If that seems like magic, well it kinda is, but the idea behind it is really simple.

There's a simple iterator protocol that can be applied to any kind of object to make the for loop work on it.

Simply implement an iterator that defines a next() method, and implement an __iter__ method on a class to make it iterable. (the __iter__ of course, should return an iterator object, that is, an object that defines next())

See official documentation

printing characters of string from the end to the beginning using range in python

for c in s[::-1]:
    print(c)

Expand alphabetical range to list of characters in Python

In [19]: s = 'B-F'

In [20]: list(map(chr, range(ord(s[0]), ord(s[-1]) + 1)))
Out[20]: ['B', 'C', 'D', 'E', 'F']

The trick is to convert both characters to their ASCII codes, and then use range().

P.S. Since you require a list, the list(map(...)) construct can be replaced with a list comprehension.

Python: Replace character RANGE in a string with new string

strings are immutable (unchangeable). But you can index and join items.

mystring = 'XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX'
mystring = 'ABCDE'.join([mystring[:20],mystring[24:]])

'XXXXXXXXXXXXXXXXXXXXABCDEXXXXXXXXXXXXXX'

Do be careful as the string length "ABCDE" and the number of items you omit between mystring[:20], mystring[24:] need to be the same length.

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