Python List Directory, Subdirectory, and Files

Python list directory, subdirectory, and files

Use os.path.join to concatenate the directory and file name:

for path, subdirs, files in os.walk(root):
    for name in files:
        print(os.path.join(path, name))

Note the usage of path and not root in the concatenation, since using root would be incorrect.

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In Python 3.4, the pathlib module was added for easier path manipulations. So the equivalent to os.path.join would be:

pathlib.PurePath(path, name)

The advantage of pathlib is that you can use a variety of useful methods on paths. If you use the concrete Path variant you can also do actual OS calls through them, like changing into a directory, deleting the path, opening the file it points to and much more.

Getting a list of all subdirectories in the current directory

Do you mean immediate subdirectories, or every directory right down the tree?

Either way, you could use os.walk to do this:

os.walk(directory)

will yield a tuple for each subdirectory. Ths first entry in the 3-tuple is a directory name, so

[x[0] for x in os.walk(directory)]

should give you all of the subdirectories, recursively.

Note that the second entry in the tuple is the list of child directories of the entry in the first position, so you could use this instead, but it's not likely to save you much.

However, you could use it just to give you the immediate child directories:

next(os.walk('.'))[1]

Or see the other solutions already posted, using os.listdir and os.path.isdir, including those at "How to get all of the immediate subdirectories in Python".

Find all files in a directory with extension .txt in Python

You can use glob:

import glob, os
os.chdir("/mydir")
for file in glob.glob("*.txt"):
    print(file)

or simply os.listdir:

import os
for file in os.listdir("/mydir"):
    if file.endswith(".txt"):
        print(os.path.join("/mydir", file))

or if you want to traverse directory, use os.walk:

import os
for root, dirs, files in os.walk("/mydir"):
    for file in files:
        if file.endswith(".txt"):
             print(os.path.join(root, file))

list all files in directory under different user python

os.listdir returns the filename without path, which makes it a relative path based on source_folder. os.path.abspath doesn't know about source_folder. All it knows about is the current working directory. So, it assumes CWD is the relative path that you want to be made absolute.

You could join the known path component before making it absolute

files = [os.path.abspath(os.path.join(source_folder, x)) 
            for x in os.listdir(source_folder)]

When using Path you have a similar problem. You created the path from the filename which lacks its path component, so Path assumes you meant the current working directory. Instead have Path do the directory enumeration for you so that it passes back properly qualified Path objects.

files = [x.absolute() for x in Path(source_folder).glob("*")]

List files ONLY in the current directory

Just use os.listdir and os.path.isfile instead of os.walk.

Example:

import os
files = [f for f in os.listdir('.') if os.path.isfile(f)]
for f in files:
    # do something

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But be careful while applying this to other directory, like

files = [f for f in os.listdir(somedir) if os.path.isfile(f)]

which would not work because f is not a full path but relative to the current directory.

Therefore, for filtering on another directory, do os.path.isfile(os.path.join(somedir, f))

(Thanks Causality for the hint)

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