Python Giving Filenotfounderror for File Name Returned by Os.Listdir

Python raising FileNotFoundError for file name returned by os.listdir

It is because os.listdir does not return the full path to the file, only the filename part; that is 'foo.txt', when open would want 'E:/somedir/foo.txt' because the file does not exist in the current directory.

Use os.path.join to prepend the directory to your filename:

path = r'E:/somedir'

for filename in os.listdir(path):
    with open(os.path.join(path, filename)) as f:
        ... # process the file

(Also, you are not closing the file; the with block will take care of it automatically).

How to avoid a FileNotFoundError with os.listdir

The path to your file is compose from root_path + your file name, you can use :

from pathlib import Path 

root_path = Path(root_dir)

for filename in os.listdir(root_path):
    if filename.endswith('.csv'):

        # Pull in the file
        df = pd.read_csv(root_path/filename)

or you can use:

for filepath in root_path.glob("*.csv"):
    df = pd.read_csv(filepath)

Getting FileNotFoundError: when I try to read the excel files in my directory

filename only contains the name of the file and not its entire path. Your script does not see the file since it's looking for it where you are and not in the directory folder. You need to add the path to the file:

import os

directory = r"C:\Users\andre\OneDrive\Desktop\python_web_scrapper\Cleaned_Data"
for filename in os.listdir(directory):
    if filename.endswith(".xlsx"):
        pd.read_excel(os.path.join(directory, filename))

listdir() No such file or directory

You try to open 'yo.jpg' in your root directory but you get your filenames from the 'path' directory.
Try to change line 11 to:

i = Image.open(path + f)

Error while using listdir in Python

I decided to change the code into:

def numOfFiles(path):
    return len(next(os.walk(path))[2])

and use the following the call the code:

print numOfFiles("client_side")

Many thanks to everyone who told me how to pass the windows directory correctly in Python and to nrao91 in here for providing the function code.

EDIT: Thank you eryksun for correcting my code!

Python says it can't find the file I am trying to rename even though it can read the file name

I thought my comment might be enough, but for clarity I'll provide a short answer.

02.png doesn't exist relative to your working directory. You need to specify the path to the file for os.rename so you need to include the directory.

import os

for file in os.listdir("./pics"):
    if file.endswith(".png"):
        newFileName = "/pics/{0}_{2}{1}".format(*os.path.splitext(file) + ("z4",)) # Notice the ./pics
        os.rename(os.path.join('pics', file), newFileName)

Python: IOError with os.listdir - files exist but are not found

Try this

import os
directoryPath=raw_input('Directory for csv files: ')
for file in os.listdir(directoryPath):
    if file.endswith(".csv"):
        filelabel=file[:-4]
        strPath = os.path.join(directoryPath, file)
        x=numpy.genfromtxt(strPath, delimiter=',')
        ans = x[:,2]

Why is os.listdir showing to a file while I set it to the directory?

shutil.rmtree deletes an entire directory tree.

To remove a single file, you can use os.remove.

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