Print in one line dynamically
Change print item
to:
print item,
in Python 2.7print(item, end=" ")
in Python 3
If you want to print the data dynamically use following syntax:
print(item, sep=' ', end='', flush=True)
in Python 3
Print dynamically in just one line
Use the end
parameter of the print
function, specifically in your example:
while i < count:
print(c, end=", ")
...
To prevent the trailing comma after the last print:
while i < count:
print(c, end=("" if i == count - 1 else ", "))
...
Print new output on same line
From help(print)
:
Help on built-in function print in module builtins:
print(...)
print(value, ..., sep=' ', end='\n', file=sys.stdout)
Prints the values to a stream, or to sys.stdout by default.
Optional keyword arguments:
file: a file-like object (stream); defaults to the current sys.stdout.
sep: string inserted between values, default a space.
end: string appended after the last value, default a newline.
You can use the end
keyword:
>>> for i in range(1, 11):
... print(i, end='')
...
12345678910>>>
Note that you'll have to print()
the final newline yourself. BTW, you won't get "12345678910" in Python 2 with the trailing comma, you'll get 1 2 3 4 5 6 7 8 9 10
instead.
Print in one line after removing previous in Python
Is this what you're looking for?
You can use sys.stdout.write('\b \b')
to delete a character already printed to the console. (Note: won't work in IDLE)
A list of these "special characters" (known as string literals) can be found here
Printing a line dynamically in python 3
import time
print('Loading', end='.')
for i in range(0,10):
print('', end=".")
time.sleep(0.5)
see explanation of end syntax and working example.
How to append a variable and print it in place of the same line before it was?
You can do this by specifying the end
argument in print()
as '\r'
or Carriage Return as it is known.
For instance:
for i in range(100):
# Your check goes here
print('[{}/100] have been checked.'.format(i), end='\r')
For the change to be noticeable you could use time.sleep()
for a small interval like 0.5 secs. Something like this:
import time
for i in range(100):
# Your check goes here
print('[{}/100] have been checked.'.format(i), end='\r')
time.sleep(0.5)
How do I make my Print Statement print on only one line?
You can pass end=''
to the print
statement so that subsequent print
s are not separated by a newline, which is the default behavior. Also, here it makes sense to use a range
iterator with for
instead of while
.
Note: I've taken the liberty to cut the sleep time in half, so it's easier to test it out.
import random
import time
All = "abcdefghijklmnopqrstuvwxyz1234567890"
for _ in range(6):
time.sleep(0.5)
print(All[random.randint(1, 35)], end='')
Print a changing variable in a for loop using one line in the ipython console
If you use sys.stdout you should be able to do it
# To see how far we're in the progress
string = '-'
for i in range(x):
sys.stdout.write('\r' + '(' + string + ' '*(max_len - len(string) + ')')
sys.stdout.flush()
string += '-'
It's important to have the '\r' character
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