How to Return Dictionary Keys as a List in Python

How to return dictionary keys as a list in Python?

This will convert the dict_keys object to a list:

list(newdict.keys())

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On the other hand, you should ask yourself whether or not it matters. It is Pythonic to assume duck typing -- if it looks like a duck and it quacks like a duck, it is a duck. The dict_keys object can be iterated over just like a list. For instance:

for key in newdict.keys():
    print(key)

Note that dict_keys doesn't support insertion newdict[k] = v, though you may not need it.

return dictionary keys with the same list values

You can convert values to tuples and use them as a key in temporary dictionary:

Try:

example_dict = {
    "list_1": [1, 2, "x"],
    "list_2": [1, 3, "x"],
    "list_3": [1, 2, "x"],
    "list_4": [1, 2, "d"],
    "list_5": [1, 3, "x"],
}

out = {}
for k, v in example_dict.items():
    out.setdefault(tuple(v), []).append(k)

print(list(v for v in out.values() if len(v) > 1))

Prints:

[['list_1', 'list_3'], ['list_2', 'list_5']]

How to specify a return type for dictionary keys in Python?

For Python 3.9, you can KeysView from the collections module to type hint your function:

from collections import KeysView

d = {'1': 1}

def keys(d: dict[str, int]) -> KeysView[str]:
    return d.keys()

Docs: https://docs.python.org/3/library/collections.abc.html#collections.abc.KeysView

For older versions, use typing.KeysView instead.

PYTHON: How to return a dictionary key if a list contains all values for that key

Iterate over your recipes dict and filter to the recipes where you have all the ingredients:

breakfast_recipes = {
    "cerealBowl" : ["milk", "cereal"],
    "toast" : ["bread", "butter"],
    "eggsBacon" : ["eggs", "bacon"],
    "frenchToast" : ["bread", "eggs"]
}

def get_recipes(ingredients):
    return {
        r: i for r, i in breakfast_recipes.items()
        if set(ingredients).issuperset(set(i))
    }

current_ingredients = ["milk", "bread", "rice", "butter", "eggs"]
print("Meals available to make...")
for r, i in get_recipes(current_ingredients).items():
    print(f"{r} with {i}")

Meals available to make...
toast with ['bread', 'butter']
frenchToast with ['bread', 'eggs']

How to change dictionary key value from a list to a single int or float in python?

Just use the dict-comprehension, where you can assign the aggregate value calling the function for the list for each keys.

>>> {k:sum(v) for k,v in ID_TypeDict.items()}
{2: 1.0, 3: 1.0, 4: 2.0}

Return dictionary keys based on list integer value

A dictionary comprehension would provide you what you need.

• You need to make sure the types agree (int vs. str)
• Unless the list is significantly longer than the dict, it will be much more efficient to iterate over the list and check that key is in the dict than the other way around.

E.g.:

In []:
new_dict = {k: my_dict[k] for k in map(int, my_list) if k in my_dict}
print(new_dict)

Out[]:
{7777777: '500'}

How to return all dictionary values and keys from function

Assuming data_dict is a list of dictionaries, let's do the same for resources, you can do something like:

def __init__(self):
    self.resources = []

def get_data(self):
    for data in data_dict:
        new_dict = {}
        new_dict['folder_id'] = data['folder_id']
        new_dict['name'] = data['name']
        self.resources.append(new_dict)
    return self.resources

Python Dictionary: Create a list for all keys in dict, another for all values in dict

Try list(Counter.keys()) and list(Counter.values())

>>> counter= Counter({'firstKey': 1708, 'secondKey': 1589, 'thirdKey': 1424})
>>> Keys = list(counter.keys())
>>> Keys
['firstKey', 'secondKey', 'thirdKey']
>>> Vals = list(counter.values())
>>> Vals
[1708, 1589, 1424]
>>> 

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