How to Make a Call to an Executable from Python Script

How to make a call to an executable from Python script?

For executing the external program, do this:

import subprocess
args = ("bin/bar", "-c", "somefile.xml", "-d", "text.txt", "-r", "aString", "-f", "anotherString")
#Or just:
#args = "bin/bar -c somefile.xml -d text.txt -r aString -f anotherString".split()
popen = subprocess.Popen(args, stdout=subprocess.PIPE)
popen.wait()
output = popen.stdout.read()
print output

And yes, assuming your bin/bar program wrote some other assorted files to disk, you can open them as normal with open("path/to/output/file.txt"). Note that you don't need to rely on a subshell to redirect the output to a file on disk named "output" if you don't want to. I'm showing here how to directly read the output into your python program without going to disk in between.

Running an outside program (executable) in Python?

Those whitespaces can really be a bother. Try os.chdir('C:/Documents\ and\ Settings/') followed by relative paths for os.system, subprocess methods, or whatever...

If best-effort attempts to bypass the whitespaces-in-path hurdle keep failing, then my next best suggestion is to avoid having blanks in your crucial paths. Couldn't you make a blanks-less directory, copy the crucial .exe file there, and try that? Are those havoc-wrecking space absolutely essential to your well-being...?

Running a C executable from Python with command line arguments

The > that you use in your command is a shell-specific syntax for output redirection. If you want to do the same through Python, you will have to invoke the shell to do it for you, with shell=True and with a single command line (not a list).

Like this:

subprocess.run(f'/home/dev/Desktop/myfile "{inputFileName}" > "{outputFileName}"', shell=True)

If you want to do this through Python only without invoking the shell (which is what shell=True does) take a look at this other Q&A: How to redirect output with subprocess in Python?

How to get a python script to run as an executable?

Add this to the top of your script

#!/usr/bin/env python

or

#!/usr/bin/env python3

depending if you want python2 or python 3

How do I execute a program or call a system command?

Use the subprocess module in the standard library:

import subprocess
subprocess.run(["ls", "-l"])

The advantage of subprocess.run over os.system is that it is more flexible (you can get the stdout, stderr, the "real" status code, better error handling, etc...).

Even the documentation for os.system recommends using subprocess instead:

The subprocess module provides more powerful facilities for spawning new processes and retrieving their results; using that module is preferable to using this function. See the Replacing Older Functions with the subprocess Module section in the subprocess documentation for some helpful recipes.

On Python 3.4 and earlier, use subprocess.call instead of .run:

subprocess.call(["ls", "-l"])

How can I make a Python script standalone executable to run without ANY dependency?

You can use py2exe as already answered and use Cython to convert your key .py files in .pyc, C compiled files, like .dll in Windows and .so on Linux.

It is much harder to revert than common .pyo and .pyc files (and also gain in performance!).

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