How to Get Char from String by Index

Get string character by index

The method you're looking for is charAt. Here's an example:

String text = "foo";
char charAtZero = text.charAt(0);
System.out.println(charAtZero); // Prints f

For more information, see the Java documentation on String.charAt. If you want another simple tutorial, this one or this one.

If you don't want the result as a char data type, but rather as a string, you would use the Character.toString method:

String text = "foo";
String letter = Character.toString(text.charAt(0));
System.out.println(letter); // Prints f

If you want more information on the Character class and the toString method, I pulled my info from the documentation on Character.toString.

How to get char from string by index?

First make sure the required number is a valid index for the string from beginning or end , then you can simply use array subscript notation.
use len(s) to get string length

>>> s = "python"
>>> s[3]
'h'
>>> s[6]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: string index out of range
>>> s[0]
'p'
>>> s[-1]
'n'
>>> s[-6]
'p'
>>> s[-7]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: string index out of range
>>>

How to get char from string by index in c language?

You need to specify the formatting string for your printfs. The first needs a string format "%s", the second a single character "%c". You can find all the details about the format used in the formatting string of printf() here.

#include <stdio.h>

int main() {
char str[11];
int num;
scanf("%s %i", &str, &num);
printf("You typed %s and %i\n", str, num);
if (num == 0)
{
printf ("%s", str);
}
else
{
printf ("%c", str[num]);
}
return 0;
}

How can I get a character in a string by index?

string s = "hello";
char c = s[1];
// now c == 'e'

See also Substring, to return more than one character.

Getting char from string at specified index

If s is your string than you could do it this way:

Mid(s, index, 1)

Edit based on comment below question.

It seems that you need a bit different approach which should be easier. Try in this way:

Dim character As String 'Integer if for numbers
's = ActiveDocument.Content.Text - we don't need it
character = Activedocument.Characters(index)

How to get letter from String by index? C++

std::string provides operator[] to access a character by index:

https://en.cppreference.com/w/cpp/string/basic_string/operator_at

Example:

const std::string s("hello");
const char c = s[0];
// c is set to ‘h’

How to get the index of each character of a string from the end

int i=sc.indexOf(sc.charAt(sc.length()-1));

should probably be

int i=sc.lastIndexOf(sc.charAt(sc.length()-1));

How to get indexes of char in the string

I assume you want to get m2rh5b7 from your input string Merhaba based on your code, then the below works fine,

        String input = "Merhaba";
StringBuilder output = new StringBuilder();
for(int i = 0; i < input.length(); i++){
char c = input.toLowerCase().charAt(i);
if(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u'){
output.append(i+1);
} else {
output.append(c);
}
}
System.out.println(output); // prints --> m2rh5b7

Or if you want just position of the vowels position only, the below is fine,


String input = "Merhaba";
for(int i = 0; i < input.length(); i++){
char c = input.toLowerCase().charAt(i);
if(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u'){
System.out.println(i);
}
}

you can use regex also, please refer the above from Alias.

How do I access a specific index in a String in java?

You are trying to access the String's characters as if it was an array of characters. You should use the charAt method instead:

char a = inputString.charAt(2);

In order for array access to work, you should first obtain the array of characters of the given String:

char[] chars = inputString.toCharArray();
char a = chars[2];

This is useful when iterating over the characters of the String.



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