Get string character by index
The method you're looking for is charAt
. Here's an example:
String text = "foo";
char charAtZero = text.charAt(0);
System.out.println(charAtZero); // Prints f
For more information, see the Java documentation on String.charAt
. If you want another simple tutorial, this one or this one.
If you don't want the result as a char
data type, but rather as a string, you would use the Character.toString
method:
String text = "foo";
String letter = Character.toString(text.charAt(0));
System.out.println(letter); // Prints f
If you want more information on the Character
class and the toString
method, I pulled my info from the documentation on Character.toString.
How to get char from string by index?
First make sure the required number is a valid index for the string from beginning or end , then you can simply use array subscript notation.
use len(s)
to get string length
>>> s = "python"
>>> s[3]
'h'
>>> s[6]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: string index out of range
>>> s[0]
'p'
>>> s[-1]
'n'
>>> s[-6]
'p'
>>> s[-7]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: string index out of range
>>>
How to get char from string by index in c language?
You need to specify the formatting string for your printfs. The first needs a string format "%s
", the second a single character "%c
". You can find all the details about the format used in the formatting string of printf()
here.
#include <stdio.h>
int main() {
char str[11];
int num;
scanf("%s %i", &str, &num);
printf("You typed %s and %i\n", str, num);
if (num == 0)
{
printf ("%s", str);
}
else
{
printf ("%c", str[num]);
}
return 0;
}
How can I get a character in a string by index?
string s = "hello";
char c = s[1];
// now c == 'e'
See also Substring
, to return more than one character.
Getting char from string at specified index
If s
is your string than you could do it this way:
Mid(s, index, 1)
Edit based on comment below question.
It seems that you need a bit different approach which should be easier. Try in this way:
Dim character As String 'Integer if for numbers
's = ActiveDocument.Content.Text - we don't need it
character = Activedocument.Characters(index)
How to get letter from String by index? C++
std::string
provides operator[]
to access a character by index:
https://en.cppreference.com/w/cpp/string/basic_string/operator_at
Example:
const std::string s("hello");
const char c = s[0];
// c is set to ‘h’
How to get the index of each character of a string from the end
int i=sc.indexOf(sc.charAt(sc.length()-1));
should probably be
int i=sc.lastIndexOf(sc.charAt(sc.length()-1));
How to get indexes of char in the string
I assume you want to get m2rh5b7
from your input string Merhaba
based on your code, then the below works fine,
String input = "Merhaba";
StringBuilder output = new StringBuilder();
for(int i = 0; i < input.length(); i++){
char c = input.toLowerCase().charAt(i);
if(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u'){
output.append(i+1);
} else {
output.append(c);
}
}
System.out.println(output); // prints --> m2rh5b7
Or if you want just position of the vowels position only, the below is fine,
String input = "Merhaba";
for(int i = 0; i < input.length(); i++){
char c = input.toLowerCase().charAt(i);
if(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u'){
System.out.println(i);
}
}
you can use regex also, please refer the above from Alias.
How do I access a specific index in a String in java?
You are trying to access the String
's characters as if it was an array of characters. You should use the charAt
method instead:
char a = inputString.charAt(2);
In order for array access to work, you should first obtain the array of characters of the given String
:
char[] chars = inputString.toCharArray();
char a = chars[2];
This is useful when iterating over the characters of the String
.
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