Dice Rolling Simulator in Python

Dice Rolling Simulator

Maybe use a for-loop and iterate over the number of times the user wants to roll the dice, while saving those to a list to display each roll of the die.

For example, the first die may look like this:

rolls = []
if dice == 'd20':
    for roll in range(number):
        rolls.append(random.randint(1,21))
    print('rolls: ', ', '.join([str(roll) for roll in rolls]))
    print('total:', sum(rolls))

Example output:

What kind of dice would you like to roll?: d20
How many times?: 2
rolls:  10, 15
total: 25

How to Make Dice Rolling in Python3

First, you will have to import a 'random' number using the 'random' number module. So the randint is a function which basically stands for Random Integer. THen you will define your functions and pass the range of numbers from which the random number will come from (0,6). So repeat=True basically helps you to play the game another more time while the .lower will convert the uppercase to the lower case in that one can choose to play the game while the caps lock is on or off.

#Dice Rolling Simulator#dice.py
from random import randint
def rand():    return randint(0,6)    repeat = Truewhile repeat:    print("You rolled",rand())    print("Do you want to roll again?")    repeat = ("y" or "yes") in input().lower()print("Game Over")

Python dice rolling simulation

You have a small typo; you are testing for equality, not assigning:

four == four+1

should be:

four = four+1

However, you already have a number between 1 and 6, why not make that into an index into the results list? That way you don't have to use so many if statements. Keep your data out of your variable names:

def rollDie(number):
    counts = [0] * 6
    for i in range(number):
        roll = random.randint(1,6)
        counts[roll - 1] += 1
    return counts

Rolling 4 dices 1000 times and counting the number of times the sum of the four dices' score is equal to 21 or higher

I fixed the problem. Can you try this

import random

n = 0   

for i in range(1000):
    dice1 = random.randint(1,6)
    dice2 = random.randint(1,6)
    dice3 = random.randint(1,6)
    dice4 = random.randint(1,6)
    sum = dice1 + dice2 + dice3 + dice4
    if sum >= 21:
        n = n + 1

print("You got 21 or higher", n, "times.")

Simulate rolling 2 dice 24 times and calculating the probability of getting a 6 in Python

random.randint(a,b) includes the endpoints a and b, so use random.randint(1,6).

Assuming you meant double 6s in the second case, you are counting double 6s more than once per trial. Compute all 24 and then check for any instance of double 6s.

Here is working code (Python 3.6):

from random import randint

trials = 1000

total = 0
for i in range(trials):
    if 6 in [randint(1,6) for j in range(4)]:
        total +=1
print(f'A 6 appeared when rolling 1 die 4 times {total/trials:.2%} of the time.')

total = 0
for i in range(trials):
    if (6,6) in [(randint(1,6),randint(1,6)) for j in range(24)]:
        total +=1
print(f'Double 6s appeared when rolling 2 dice 24 times {total/trials:.2%} of the time.')

Output:

A 6 appeared when rolling 1 die 4 times 50.30% of the time.
Double 6s appeared when rolling 2 dice 24 times 48.90% of the time.

Dice Rolling Simulator in Python