Create Dynamic Urls in Flask with Url_For()

Create dynamic URLs in Flask with url_for()

It takes keyword arguments for the variables:

url_for('add', variable=foo)
url_for('remove', variable=foo)

The flask-server would have functions:

@app.route('/<variable>/add', methods=['GET', 'POST'])
def add(variable):

@app.route('/<variable>/remove', methods=['GET', 'POST'])
def remove(variable):

Pass dynamic url parameter for flask url_for

Pass it as second argument to url_for

{{ url_for('home.downloads', application_name = "YOUR DYNAMIC APP NAME") }}

Edit:

For the dynamic one, you simply pass the variable.

{{ url_for('home.downloads', application_name = application) }}

and when you are rendering the template, send your dynamic value.

     application = "DO WHATEVER AND ASSIGN THE VALUE HERE"
     return render_template("template.html", application = application )

Refer: https://flask.palletsprojects.com/en/2.1.x/quickstart/#url-building

Flask - Creating dynamic URL based on user input

You are coming at it from the wrong way. When Jinja creates index.html based on your template you can't know what variable is going to be, so how is Jinja supposed to know?

What you need to do is send the form back to the same route and then redirect the user to whatever they typed in. So something like this:

from flask import request, redirect, url_for

@app.route("/", methods=['GET', 'POST'])
def markert_hours_today():
    if request.method == 'POST':
        result = request.form['variable']
        return redirect(url_for('ticker_result', variable=result)
    return render_template("index.html")

Edit: forgot to rename variable from user_input to result.

Create dynamic arguments for url_for in Flask

Any arguments that don't match route parameters will be added as the query string. Assuming extra_args is a dict, just unpack it.

extra_args = {'hello': 'world'}
url_for('doit', oid=oid, **extra_args)
# /doit/123?hello=world
url_for('doit', oid=oid, hello='davidism')
# /doit/123?hello=davidism

Then access them in the view with request.args:

@app.route('/doit/<int:oid>')
def doit(oid)
    hello = request.args.get('hello')
    ...

how to create a dynamic url from form using flask

The answer was to add an if statement to the form. Otherwise it errors out

@app.route("/", methods=['POST', 'GET'])
def home():

    if request.form:
        project_select = request.form['project']
        return redirect(url_for("project_page", project=project_select))
    else:
        return render_template("home.html", list_projects=list_projects)

Best method for dynamically building URL with Flask url_for

If the elements of last_orders contain the prefix used in the xxx_page function(s), then you can just make an a tag within the td.

<td><a href={{ url_for('{}_page'.format(x)) }}>something here</a></td>

EDIT: After rereading your question, you're looking to make the entire cell clickable. There are a couple options in JavaScript. You can listen to clicks on all the td elements, and then trigger a click on their child a.

# Don't actually use an anonymous function. Define it elsewhere.
$('body').off('click.order')
    .on('click.order', 'td', function(e) {
        $(this).find('a').trigger('click');
    });

OR (and I like this option much less than the first one) you could set a data element on the td elements with the address.

<td data-url='{{ url_for('{}_page'.format(x)) }}'>something here</td>

Then in your click listener, do this.

window.location.href = $(this).attr('data-url');

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