Countdown Timer in Pygame

Countdown timer in Pygame

On this page you will find what you are looking for http://www.pygame.org/docs/ref/time.html#pygame.time.get_ticks


You download ticks once before beginning the countdown (which can be a trigger in the game - the key event, whatever).
For example:

start_ticks=pygame.time.get_ticks() #starter tick
while mainloop: # mainloop
    seconds=(pygame.time.get_ticks()-start_ticks)/1000 #calculate how many seconds
    if seconds>10: # if more than 10 seconds close the game
        break
    print (seconds) #print how many seconds

How to make a circular countdown timer in Pygame?

Just use pygame.draw.arc and specify the stop_angle argument depending on the counter:

percentage = counter/100
end_angle = 2 * math.pi * percentage
pygame.draw.arc(window, (255, 0, 0), arc_rect, 0, end_angle, 10)

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Minimal example:

import pygame
import math

pygame.init()
window = pygame.display.set_mode((200, 200))
clock = pygame.time.Clock()
font = pygame.font.SysFont(None, 100)
counter = 100
text = font.render(str(counter), True, (0, 128, 0))

timer_event = pygame.USEREVENT+1
pygame.time.set_timer(timer_event, 1000)

def drawArc(surf, color, center, radius, width, end_angle):
    arc_rect = pygame.Rect(0, 0, radius*2, radius*2)
    arc_rect.center = center
    pygame.draw.arc(surf, color, arc_rect, 0, end_angle, width)

run = True
while run:
    clock.tick(60)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False
        elif event.type == timer_event:
            counter -= 1
            text = font.render(str(counter), True, (0, 128, 0))
            if counter == 0:
                pygame.time.set_timer(timer_event, 0)                

    window.fill((255, 255, 255))
    text_rect = text.get_rect(center = window.get_rect().center)
    window.blit(text, text_rect)
    drawArc(window, (255, 0, 0), (100, 100), 90, 10, 2*math.pi*counter/100)
    pygame.display.flip()

pygame.quit()
exit()

Sadly the quality of pygame.draw.arc with a width > 1 is poor. However this can be improved, using cv2 and cv2.ellipse:

import pygame
import cv2
import numpy

pygame.init()
window = pygame.display.set_mode((200, 200))
clock = pygame.time.Clock()
font = pygame.font.SysFont(None, 100)
counter = 100
text = font.render(str(counter), True, (0, 128, 0))

timer_event = pygame.USEREVENT+1
pygame.time.set_timer(timer_event, 1000)

def drawArcCv2(surf, color, center, radius, width, end_angle):
    circle_image = numpy.zeros((radius*2+4, radius*2+4, 4), dtype = numpy.uint8)
    circle_image = cv2.ellipse(circle_image, (radius+2, radius+2),
        (radius-width//2, radius-width//2), 0, 0, end_angle, (*color, 255), width, lineType=cv2.LINE_AA) 
    circle_surface = pygame.image.frombuffer(circle_image.flatten(), (radius*2+4, radius*2+4), 'RGBA')
    surf.blit(circle_surface, circle_surface.get_rect(center = center))

run = True
while run:
    clock.tick(60)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False
        elif event.type == timer_event:
            counter -= 1
            text = font.render(str(counter), True, (0, 128, 0))
            if counter == 0:
                pygame.time.set_timer(timer_event, 0)                

    window.fill((255, 255, 255))
    text_rect = text.get_rect(center = window.get_rect().center)
    window.blit(text, text_rect)
    drawArcCv2(window, (255, 0, 0), (100, 100), 90, 10, 360*counter/100)
    pygame.display.flip()

pygame.quit()
exit()

Python Countdown Timer

In python, \rin a string stands for the carriage return character. It does reset the position of the cursor to the start of the current line. The end argument in the print function is the string that is printed after the given text. By default, this is \n, a newline character.

In the timer we do want that the new time overwrites the previous one, not that the new time is printed after the previous one. Thus, the end argument of the print function is set to \r, such that the cursor is moved to the back of the line. This makes thet the new time is printed over the new one.

Creating a countdown timer in Pygame

Yes this is possible using the pygame.time.Clock. You just use the tick method with the fps that you want. But keep in mind you are only going to see updates as fast as your screen refreshes.

clock = pygame.time.Clock()
while True:
    clock.tick(1000)  # waits until the next ms
    #clear your frame here
    #update and draw your text here
    #flip your display window here

How to start a countdown when pygame.QUIT is initialized

Instead of exiting the application, start a countdown timer. Quit the application when the countdown is complete.

See Countdown timer in Pygame.

Minimal example:

import pygame

pygame.init()
window = pygame.display.set_mode((200, 200))
clock = pygame.time.Clock()
font = pygame.font.SysFont(None, 100)
counter = 0
text = font.render(str(10), True, (0, 128, 0))

timer_event = pygame.USEREVENT+1

run = True
while run:
    clock.tick(60)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            counter = 10
            pygame.time.set_timer(timer_event, 1000)
        elif event.type == timer_event:
            counter -= 1
            text = font.render(str(counter), True, (0, 128, 0))
            if counter == 0:
                run = False             

    window.fill((255, 255, 255))
    
    # draw game
    # [...]
    
    if counter > 0:
        text_rect = text.get_rect(center = window.get_rect().center)
        window.blit(text, text_rect)

    pygame.display.flip()

pygame.quit()
exit()

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