Call Python Script from Bash With Argument

Call Python script from bash with argument

To execute a python script in a bash script you need to call the same command that you would within a terminal. For instance

> python python_script.py var1 var2

To access these variables within python you will need

import sys
print(sys.argv[0]) # prints python_script.py
print(sys.argv[1]) # prints var1
print(sys.argv[2]) # prints var2

How to call a python script from bash with arguments?

I think you have just to add you argument at in same line as python command. like this

python yt_up.py --file="${_file}" –-title="${_file}" --description="show 2018" --keywords="2018,show, Winter,show 2018," -–category="28" --privacyStatus="private"

It works

Pass arguments to python from bash script

You use $@ in tinify.sh

#!/bin/bash
tinify.py "$@"

It will be far easier to eliminate duplicates inside the Python script that to filter them out from the shell. (Of course, this raises the question whether you need a shell script at all.)

Python: subprocess and running a bash script with multiple arguments

Pass arguments as a list, see the very first code example in the docs:

import subprocess

subprocess.check_call(['/my/file/path/programname.sh', 'arg1', 'arg2', arg3])

If arg3 is not a string; convert it to string before passing to check_call(): arg3 = str(arg3).

passing an argument to a python function from bash

Don't interpolate string variables into the command; pass the value as an argument to the Python script.

python -c 'import sys, sample; sample.printFxn(sys.argv[1])' "$fileName"

Unable to run python script from bash scripts with string arguments

This was solved by changing contents of jobFile.sh

#!/bin/bash

srun python generate.py -p "Flower girl"

exit 0

commands.txt is not required anymore.

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