Appending List But Error 'Nonetype' Object Has No Attribute 'Append'

NoneType' object has no attribute 'append' python

d.append(i) returns None
therefore:

d = d.append(i) assigns None to d

replace that line with:

d.append(i)

The same goes for c = c.append(i)

Appending to list with 'NoneType' object has no attribute 'append'' error

Campaign_info_1 = Campaign_info_1.append(Campaign_info) must be changed to Campaign_info_1.append(Campaign_info). Append mutates the list, reassignment is not necessary and causes the error.

Campaign_info_1 = list()
for Detail in I_Details:
  Campaign_info = Detail.contents
  Campaign_info = str(Campaign_info)
  if Campaign_info==None or Campaign_info=="": 
    pass 
  Campaign_info_1.append(Campaign_info) 
  print(Campaign_info)

NoneType' object has no attribute 'append'. How to append int to list in a loop?

append does not return a list, it changes the state of the list on which it's called. Therefore, when you assign p = p.append(3), you're assigning p the value of None, and hence you get the error you cited.

To fix this, simply eliminate the assignment in the loop.

p = [] 
for x in range(24):
    p.append(3)
    print(p)

AttributeError: 'NoneType' object has no attribute 'append' no matter what

append doesn't return anything. The last line should just be:

vdf_big_list.append(vdf_s_lines_list)

Python : AttributeError: 'NoneType' object has no attribute 'append'

Actually you stored None here:
append() changes the list in place and returns None

 item_to_bucket_list_map[i] = (item_to_bucket_list_map.get(i)).append(j)

example:

In [42]: lis = [1,2,3]

In [43]: print lis.append(4)
None

In [44]: lis
Out[44]: [1, 2, 3, 4]

---

Related Topics