Validate Date Format in PHP

PHP Regex to check date is in YYYY-MM-DD format

Try this.

$date="2012-09-12";

if (preg_match("/^[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1])$/",$date)) {
    return true;
} else {
    return false;
}

Correctly determine if date string is a valid date in that format

You can use DateTime::createFromFormat() for this purpose:

function validateDate($date, $format = 'Y-m-d')
{
    $d = DateTime::createFromFormat($format, $date);
    // The Y ( 4 digits year ) returns TRUE for any integer with any number of digits so changing the comparison from == to === fixes the issue.
    return $d && $d->format($format) === $date;
}

^{[Function taken from this answer. Also on php.net. Originally written by Glavić.]}

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Test cases:

var_dump(validateDate('2013-13-01'));  // false
var_dump(validateDate('20132-13-01')); // false
var_dump(validateDate('2013-11-32'));  // false
var_dump(validateDate('2012-2-25'));   // false
var_dump(validateDate('2013-12-01'));  // true
var_dump(validateDate('1970-12-01'));  // true
var_dump(validateDate('2012-02-29'));  // true
var_dump(validateDate('2012', 'Y'));   // true
var_dump(validateDate('12012', 'Y'));  // false

Demo!

How to check format of Date in PHP?

From the PHP manual on strtotime

Dates in the m/d/y or d-m-y formats are disambiguated by looking at
the separator between the various components: if the separator is a
slash (/), then the American m/d/y is assumed; whereas if the
separator is a dash (-) or a dot (.), then the European d-m-y format
is assumed. To avoid potential ambiguity, it's best to use ISO 8601
(YYYY-MM-DD) dates or DateTime::createFromFormat() when possible.

The reason passing the date to SQL server works as mm/dd/yyyy is because of the separator. Where possible it is always best to pass as YYYY-MM-DD as per ISO 8601 which was created for exactly this purpose. To fix your problem the best bet is to change the jQuery plugin configuration to output data in that format (if that's not possible, string replace / with - where it's coming from the jQuery plugin. This will avoid future complications by writing code to fix the date format.

You will no be able to tell the difference between mm/dd/yyyy and dd/mm/yyyy when you don't know where it's come from.

Validate date format in php

function _date_is_valid($str) {
    if (substr_count($str, '/') == 2) {
        list($d, $m, $y) = explode('/', $str);
        return checkdate($m, $d, sprintf('%04u', $y));
    }

    return false;
}

Verify valid date using PHP's DateTime class

You can try this one:

static public function verifyDate($date)
{
    return (DateTime::createFromFormat('m/d/Y', $date) !== false);
}

This outputs true/false. You could return DateTime object directly:

static public function verifyDate($date)
{
    return DateTime::createFromFormat('m/d/Y', $date);
}

Then you get back a DateTime object or false on failure.

UPDATE:

Thanks to Elvis Ciotti who showed that createFromFormat accepts invalid dates like 45/45/2014.
More information on that: https://stackoverflow.com/a/10120725/1948627

I've extended the method with a strict check option:

static public function verifyDate($date, $strict = true)
{
    $dateTime = DateTime::createFromFormat('m/d/Y', $date);
    if ($strict) {
        $errors = DateTime::getLastErrors();
        if (!empty($errors['warning_count'])) {
            return false;
        }
    }
    return $dateTime !== false;
}

php date validation

You could use checkdate. For example, something like this:

$test_date = '03/22/2010';
$test_arr  = explode('/', $test_date);
if (checkdate($test_arr[0], $test_arr[1], $test_arr[2])) {
    // valid date ...
}

A more paranoid approach, that doesn't blindly believe the input:

$test_date = '03/22/2010';
$test_arr  = explode('/', $test_date);
if (count($test_arr) == 3) {
    if (checkdate($test_arr[0], $test_arr[1], $test_arr[2])) {
        // valid date ...
    } else {
        // problem with dates ...
    }
} else {
    // problem with input ...
}

validate invalid date character using php

Try This :

E better class for validating and formatting dates Without DateTime function :

http://www.tonymarston.net/php-mysql/dateclass.html

Or

You could use PHP's DateTime class:

function validateDate($date)
{
    $d = DateTime::createFromFormat('Y/m/d', $date);
    return $d && $d->format('Y/m/d') == $date;
}

^{function was copied from this answer or php.net}

Validating a custom date format in with laravel validator

The easier option is to use the Laravel date_format:format
rule (https://laravel.com/docs/5.5/validation#rule-date-format). It's a built-in function in Laravel without the need for a custom rule (available in Laravel 5.0+).

You can do:

$rule['date'] = 'required|date_format:d/m/Y';

or

$rule['date'] = 'required|date_format:Y-m-d';

PHP check user input date

You can use a combination of strtotime() and checkdate() to see if the date is valid:

function isRealDate($date) { 
    if (false === strtotime($date)) { 
        return false;
    } 
    list($year, $month, $day) = explode('-', $date); 
    return checkdate($month, $day, $year);
}

usage

if (isRealDate($geboortedatum)) {
    // date is ok
}
else {
    // date is not ok
}

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