Sort an Array by Keys Based on Another Array

Sort an Array by keys based on another Array?

Just use array_merge or array_replace. array_merge works by starting with the array you give it (in the proper order) and overwriting/adding the keys with data from your actual array:

$customer['address']    = '123 fake st';
$customer['name']       = 'Tim';
$customer['dob']        = '12/08/1986';
$customer['dontSortMe'] = 'this value doesnt need to be sorted';

$properOrderedArray = array_merge(array_flip(array('name', 'dob', 'address')), $customer);
// or
$properOrderedArray = array_replace(array_flip(array('name', 'dob', 'address')), $customer);

// $properOrderedArray: array(
//   'name'       => 'Tim',
//   'dob'        => '12/08/1986',
//   'address'    => '123 fake st',
//   'dontSortMe' => 'this value doesnt need to be sorted')

PS: I'm answering this 'stale' question, because I think all the loops given as previous answers are overkill.

Sort array elements based on another array's keys

How about this? Using array_replace():

<?php
$arr1 = array('0' => 'John', '1' => 'George', '2' => 'James', '3' => 'Harry');
$arr2 = array('0' => '12', '1' => '8', '2' => '34', '3' => '23');
arsort($arr2);
var_dump(array_replace($arr2, $arr1)); // array(4) { [2]=> string(5) "James" [3]=> string(5) "Harry" [0]=> string(4) "John" [1]=> string(6) "George" }

Demo

Javascript - sort array based on another array

One-Line answer.

itemsArray.sort(function(a, b){  
  return sortingArr.indexOf(a) - sortingArr.indexOf(b);
});

Or even shorter:

itemsArray.sort((a, b) => sortingArr.indexOf(a) - sortingArr.indexOf(b));

PHP - Sort array with another array

$ordered_fruits = array();
foreach($order as $value) {

   if(array_key_exists($value,$fruits)) {
      $ordered_fruits[$value] = $fruits[$value];
   }
}

Sort object array based on another array of keys

Try this

var a = ['d','a','b','c'] ;var b =  [{a:1},{c:3},{d:4},{b:2}];
b.sort(function(x,y){  var xkey = a.indexOf(Object.keys(x)[0]);  var ykey = a.indexOf(Object.keys(y)[0]);  return xkey - ykey;})
document.body.innerHTML += JSON.stringify(b,0,4);

const array1 = [
    {
        "name": "B",
        "order": 1
    },
    {
        "name": "C",
        "order": 2
    },
    {
        "name": "D",
        "order": 3
    },
    {
        "name": "B",
        "order": 4
    },
    {
        "name": "A",
        "order": 5
    }
]

const array2 = [
    {
        "name": "B",
        "order": 1,
        "id": 3638
    },
    {
        "name": "B",
        "order": 1,
        "id": 3661
    },
    {
        "name": "C",
        "order": 2,
        "id": 3658
    },
    {
        "name": "D",
        "order": 3,
        "id": 3659
    },
    {
        "name": "A",
        "order": 5,
        "id": 3636
    }
]

const sortedArray2 = []

for(const item of array1) {
    sortedArray2.push(
        array2.splice(
            array2.findIndex(elem => elem.name === item.name), 1
        )
    )
}

console.log(sortedArray2)

var arrayObject = [{key: 'g'},{key: 'a'},{key: 'b'},{key: 'c'},{key: 'd'},{key: 'e'}];
var array = ['a', 'c', 'd', 'e'];
arrayObject.forEach(o => {  if (!array.includes(o.key)) array.push(o.key)})
// now your code works fine let result = arrayObject.sort((a, b) => {    return array.indexOf(a.key) - array.indexOf(b.key); });
console.log(result)