Pretty-printing Json With PHP

Pretty-Printing JSON with PHP

PHP 5.4 offers the JSON_PRETTY_PRINT option for use with the json_encode() call.

http://php.net/manual/en/function.json-encode.php

<?php
...
$json_string = json_encode($data, JSON_PRETTY_PRINT);

How to pretty print JSON with wp_json_encode()?

You can make use of wp_json_encode() options parameter.

Setting options to JSON_PRETTY_PRINT as an argument will make the function use whitespace in returned data to format it:

wp_json_encode($data, JSON_PRETTY_PRINT);

PHP pretty print json_encode

PHP has JSON_PRETTY_PRINT option since 5.4.0 (release date 01-Mar-2012).

This should do the job:

$json = json_decode($string);
echo json_encode($json, JSON_PRETTY_PRINT);

See http://www.php.net/manual/en/function.json-encode.php

Note: Don't forget to echo "<pre>" before and "</pre>" after, if you're printing it in HTML to preserve formatting ;)

JSON pretty print without use json_decode in php

Only a parser can understand the JSON, so you can either do what you proposed or write your own parser. If you have access to the origin of the JSON, make it pretty in the first place.

Pretty print JSON that's already encoded in PHP

json_encode($json, JSON_PRETTY_PRINT); 

Save it like that then display it with <pre> and <code>(if needed) tags wrapped around it..

Json encode PRETTY PRINT printing out with slashes in php

The data you get from wp_remote_get is already a perfectly encoded JSON string, no need to encode again.

When you encode again, PHP generates a structure with one element, the string you originally get, and escapes all the quotes to form valid JSON.

So you can output the data directly :

$response = wp_remote_get( 'URL TO JSON DATA' ));
header('Content-Type: application/json');
echo $response;

How to log pretty printed json in PHP?

error_log("test\n" . json_encode($json_string, JSON_PRETTY_PRINT));

json_encode() will actually not necessarily produce JSON: it will produce something that can be read by javascript. If you give it an array or an object, it will produce JSON; if you give it a string, it will produce a javascript string. And that’s what you’re doing, so that’s what you’re getting.

To be clear, $json_string is a string: (as far as PHP is concerned, it’s a string; if you passed that same string to javascript, it would be interpreted as an object). You pass that through json_encode() and all you’re going to get is another string (a string of doubly-encoded JSON).

JSON_PRETTY_PRINT is having no effect here, because you’re not producing JSON: you’re producing something that javascript too would see as a string.

Savvy?

So what you need to do is to (a) turn $json_string back into a PHP array, and then (b) reencode that as JSON, this time using the JSON_PRETTY_PRINT flag.

$log_array = json_decode($json_string, true);
$json_pretty_string = json_encode($log_array, JSON_PRETTY_PRINT);
error_log('test' . PHP_EOL . $json_pretty_string);

Rather than converting it back to a PHP array and then back to JSON, it would be better to add the JSON_PRETTY_PRINT flag to wherever you’re getting $json_string from in the first place, if possible.

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Alternatively, just log $json_string directly (no need to encode it: it’s already a string, you can pass it to error_log() as it is), and worry about prettifying it only when you need to read your logs. This will make your logs considerably smaller.

Why the code is not printing in Pretty Json format?

You just need to add a second a parameter to json_encode() and add <pre> tag. Like this:

echo '<pre>';
echo json_encode($data, JSON_PRETTY_PRINT);
echo '</pre>';

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