PHP Explode the String, But Treat Words in Quotes as a Single Word

PHP explode the string, but treat words in quotes as a single word

You could use a preg_match_all(...):

$text = 'Lorem ipsum "dolor sit amet" consectetur "adipiscing \\"elit" dolor';
preg_match_all('/"(?:\\\\.|[^\\\\"])*"|\S+/', $text, $matches);
print_r($matches);

which will produce:

Array
(
    [0] => Array
        (
            [0] => Lorem
            [1] => ipsum
            [2] => "dolor sit amet"
            [3] => consectetur
            [4] => "adipiscing \"elit"
            [5] => dolor
        )

)

And as you can see, it also accounts for escaped quotes inside quoted strings.

EDIT

A short explanation:

"           # match the character '"'
(?:         # start non-capture group 1 
  \\        #   match the character '\'
  .         #   match any character except line breaks
  |         #   OR
  [^\\"]    #   match any character except '\' and '"'
)*          # end non-capture group 1 and repeat it zero or more times
"           # match the character '"'
|           # OR
\S+         # match a non-whitespace character: [^\s] and repeat it one or more times

And in case of matching %22 instead of double quotes, you'd do:

preg_match_all('/%22(?:\\\\.|(?!%22).)*%22|\S+/', $text, $matches);

PHP explode strings, but treat words in quotes as a single word

You may use

if (preg_match_all('~(?|"([^\\\\"]*(?:\\\\.[^"\\\\]*)*)"|([^\s"]+))~s', $s, $matches)) 
{
    print_r($matches[1]);
}

See the regex demo.

Details

(?| - starts a branch reset group:
- " - a " char
- ([^\\\\"]*(?:\\\\.[^"\\\\]*)*) - Group 1: any 0+ chars other than \ and " followed with 0 or more repetitions of any escaped char and then any 0+ chars other than \ and "
- " - a " char
| - or
- ([^\s"]+) - Group 1: one or more chars other than whitespace and "
) - end of the branch reset group.

See the PHP demo:

$s = '"foo bar"ANDbar"foo"AND"foofoo" lorem "impsum"';
if (preg_match_all('~(?|"([^\\\\"]*(?:\\\\.[^"\\\\]*)*)"|([^\s"]+))~s', $s, $matches)) 
{
    print_r($matches[1]);
}
// => Array ( [0] => foo bar [1] => ANDbar [2] => foo [3] => AND [4] => foofoo [5] => lorem [6] => impsum )

PHP explode the string, but treat words in quotes as a single word and ignore brackets

The reason is that the regex you use is meant to keep standalone " in the matches.

If you are sure the unescaped double quotes are always paired in your input, use

'/"(?:\\\\.|[^\\\\"])*"|[^\s"]+/'
                        ^^^^^^

Exclude the " from \S by turning it into a negative character class [^\s] and add the double quote inside.

To include single quoted substrings, you may use

'~"(?:\\\\.|[^\\\\"])*"|\'(?:\\\\.|[^\\\\\'])*\'|[^\s"\']+~'

See the regex demo and a PHP demo:

$re = '~"(?:\\\\.|[^\\\\"])*"|\'(?:\\\\.|[^\\\\\'])*\'|[^\s"\']+~';
$str = 'Lorem ipsum ("dolor sit amet") consectetur "adipiscing \\"elit" dolor \'something  \\\'here\'';
preg_match_all($re, $str, $matches);
print_r($matches[0]);
// => Array ( [0] => Lorem [1] => ipsum [2] => ( [3] => "dolor sit amet" [4] => )
//   [5] => consectetur [6] => "adipiscing \"elit" [7] => dolor [8] => 'something  \'here' )

R: Explode string but keep quoted text as a single word

A simple option would be to use scan:

> x <- scan(what = "", text = mystr)
Read 11 items
> x
 [1] "preceded by itself in quotation marks forms a complete sentence"
 [2] "preceded"                                                       
 [3] "by"                                                             
 [4] "itself"                                                         
 [5] "in"                                                             
 [6] "quotation"                                                      
 [7] "marks"                                                          
 [8] "forms"                                                          
 [9] "a"                                                              
[10] "complete"                                                       
[11] "sentence"

Split string on spaces except words in quotes

You can use:

$string = 'Some of "this string is" in quotes';
$arr = preg_split('/("[^"]*")|\h+/', $string, -1, 
                   PREG_SPLIT_NO_EMPTY|PREG_SPLIT_DELIM_CAPTURE);
print_r ( $arr );

Output:

Array
(
    [0] => Some
    [1] => of
    [2] => "this string is"
    [3] => in
    [4] => quotes
)

RegEx Breakup

("[^"]*")    # match quoted text and group it so that it can be used in output using
             # PREG_SPLIT_DELIM_CAPTURE option
|            # regex alteration
\h+          # match 1 or more horizontal whitespace

An explode() function that ignores characters inside quotes?

str_getcsv($str, '/')

There's a recipe for <5.3 on the linked page.

Exploding string on space but not spaces in quotation marks

You could use regex:

$string = 'test1 test2 "test3 test4"';
preg_match_all('/\"[\s\S]+\")|([\S]+)/ism', $string, $matches);

print_r($matches);

Alternatively, you could try using str_getcsv()

PHP string explode on space, except when in quotes