PHP Check If Date Between Two Dates

PHP check if date between two dates

Edit: use <= or >= to count today's date.

This is the right answer for your code. Just use the strtotime() php function.

$paymentDate = date('Y-m-d');
$paymentDate=date('Y-m-d', strtotime($paymentDate));
//echo $paymentDate; // echos today! 
$contractDateBegin = date('Y-m-d', strtotime("01/01/2001"));
$contractDateEnd = date('Y-m-d', strtotime("01/01/2012"));
    
if (($paymentDate >= $contractDateBegin) && ($paymentDate <= $contractDateEnd)){
    echo "is between";
}else{
    echo "NO GO!";  
}

Check the date between two dates

You are checking with || in your case you need to use && because you need date BETWEEN

$date1 = '20-08-2017';
$date2 = date('d-m-Y' , strtotime('-3 months'));
$date3 = date('d-m-Y' , strtotime('-6 months'));
if((strtotime($date1) <= strtotime($date2)) && (strtotime($date1) >= strtotime($date3))){
    echo "Inside Range";
}else { 
   echo "Out of Range";
}

Explanation:
Need to change your condition from if((strtotime($date1) < strtotime($date2)) || (strtotime($date1) > strtotime($date3))) to if((strtotime($date1) <= strtotime($date2)) && (strtotime($date1) >= strtotime($date3))){

It's also significantly easier if you're using DateTime objects:

$date1 = new DateTime('20-08-2017');
$date2 = new DateTime('-3 months');
$date3 = new DateTime('-6 months');

if($date1 < $date2 && $date1 > $date3) {
    echo "Inside Range";
} else {
    echo "Out of Range";
}

PHP check if today is in between two dates

Try this:

<?php

    $now = new DateTime();
    $startdate = new DateTime("2014-11-20");
    $enddate = new DateTime("2015-01-20");

    if($startdate <= $now && $now <= $enddate) {
        echo "Yes";
    }else{
        echo "No";
    }

?>

php how to check if date string in between dates

The function strtotime() is what you need. It takes a dateable string and converts it into seconds elapsed from epoch.

In simple terms:

if (strtotime(str_replace("/", "-", "18/10/2018")) > strtotime(str_replace("/", "-", "20/10/2018")))
  echo "Greater";
else
  echo "Smaller";

Just a heads up:

strtotime("18-10-2018")
int(1539835200)

strtotime("20-10-2018")
int(1540008000)

You might need to replace the separator as:

Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed. If, however, the year is given in a two digit format and the separator is a dash (-), the date string is parsed as y-m-d.
To avoid potential ambiguity, it's best to use ISO 8601 (YYYY-MM-DD) dates or DateTime::createFromFormat() when possible.

check if date is between two dates without year

You only wish to compare on the m and d annually, so only create a string to compare against that consists of m-d. Then you can shorten your start and end dates to only be m-d as well. Because you have formatted your dates from bigger unit to smaller unit (month then day), you can simply compare the dates as regular strings.

Code: (Demo)

$now = date('m-d');
$start_md = "12-06";
$end_md = "12-27";

if ($start_md <= $now && $now <= $end_md) {
  echo "Christmas time";
} else {
  echo "Not christmas time";
}

PHP if between 2 dates

if (($date >= $snowStart) && ($date <= $snowEnd)) 
{
     // do this and that
}