Passing an Array as Arguments, Not an Array, in PHP

Passing an Array as Arguments, not an Array, in PHP

http://www.php.net/manual/en/function.call-user-func-array.php

call_user_func_array('func',$myArgs);

Passing an Array as Arguments in php

Try something like:

call_user_func_array(array($stmt,'bind_param'),$request['params']);

Passing an Array as an Argument

The first answer for the question you link shows call_user_func_array(), so with an object method do:

$res = call_user_func_array(array($geo, $method), $params);

Can we pass an array as parameter in any function in PHP?

You can pass an array as an argument. It is copied by value (or COW'd, which essentially means the same to you), so you can array_pop() (and similar) all you like on it and won't affect anything outside.

function sendemail($id, $userid){
    // ...
}

sendemail(array('a', 'b', 'c'), 10);

You can in fact only accept an array there by placing its type in the function's argument signature...

function sendemail(array $id, $userid){
    // ...
}

You can also call the function with its arguments as an array...

call_user_func_array('sendemail', array('argument1', 'argument2'));

Passing an array as the parameter of a function in PHP

Try this. It will create a function that has a reference to your array. When you change the array you can call the product of the function, and it will recalculate the sum.

$array = ['English' => '12', 'Swedish' => '12'];

function arraySumCb(&$subject) {
  return function () use (&$subject) {
    return array_sum($subject);
  };
}

$sum = arraySumCb($array);
echo $sum(); // 24
$array['Swedish'] = '15';
echo $sum(); // 27
$array['Swedish'] = '10';
echo $sum(); // 22

Edit: This is how I would do it.

$array = ['English' => '12', 'Swedish' => '12'];

class SumMarks {
  private $_subject;
  public function __construct(array &$subject = []) {
    $this->_subject = &$subject;
  }

  public function __toString() {
    return "" . array_sum($this->_subject);
  }
}

$sum = new SumMarks($array);

echo $sum; // 24

$array['Swedish'] = '10';

echo $sum; // 22

Edit: Proper use of PHP anonymous functions

Pass array as argument list to function

You can use call_user_func_array.

Use like:

$array = array(1, 2, 3);
call_user_func_array("myfunc", $array);

function myfunc($a, $b, $c) {
    var_dump($a, $b, $c); // 1 2 3
}

---

$array = array(2, 3);
$first = 1;
call_user_func_array("myfunc", array_merge(arary($first), $array));

function myfunc($a, $b, $c) {
    var_dump($a, $b, $c); // 1 2 3
}

---

In case of an object instance your callback should look like:

array($obj, "someFunc")

so:

call_user_func_array(array($obj, "someFunc"), $array);

Passing and using an array by reference in PHP

I just ran your code and got the expected output, so I'm not sure what's happening. If arr wasn't an array, it wouldn't pass the typehint, so it's definitely an array.

It's possible that you're running PHP < 5.4

<?php

function foo(array &$arr) {
    $arr[] = "error on this line";
    $arr[] = "more";
    $arr[] = "stuff";
}

$a = ["initial"];

foo($a);

var_dump($a);

/*
array(4) {
  [0] =>
  string(7) "initial"
  [1] =>
  string(18) "error on this line"
  [2] =>
  string(4) "more"
  [3] =>
  string(5) "stuff"
}
*/

For PHP < 5.4:

<?php

function foo(array &$arr) {
    array_push($arr, "error on this line");
    array_push($arr, "more");
    array_push($arr, "stuff");
}

$a = array("initial");

foo($a);

var_dump($a);

/*
array(4) {
  [0] =>
  string(7) "initial"
  [1] =>
  string(18) "error on this line"
  [2] =>
  string(4) "more"
  [3] =>
  string(5) "stuff"
}
*/

Function is expecting arrays but I want to pass a variable

You can use call_user_func_array to accomplish that.

$arrs = array(
    array('blue', 'green', 'red'),
    array('apples', 'oranges', 'bananas')
);

call_user_func_array('cartesianProduct', $arrs);

The first argument is the function name you want to call and the second is an indexed array of parameters that will be passed to it.

How to pass an array as a parameter in a class constructor in PHP

Add:

$this->tableFields = $tableFields;

And:

$myObject = new GenerateCrud('users_test', 'id', ['field1', 'field2', 'field3', 'field4']);

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