What's wrong? PHP Parse error: syntax error, unexpected '}', expecting ',' or ';' in
You missed ;
. Each statement must ends up with a semicolon in PHP.
Parse error: syntax error, unexpected '.', expecting ',' or ';'
Static class properties are initialized at compile time. You cannot use a constant TABLE_PREFIX
to concatenate with a string literal when initializing a static class property, since the constant's value is not known until runtime. Instead, initialize it in the constructor:
public static $user_table;
// Initialize it in the constructor
public function __construct() {
self::$user_table = TABLE_PREFIX . 'users';
}
// If you only plan to use it in static context rather than instance context
// (won't call a constructor) initialize it in a static function instead
public static function init() {
self::$user_table = TABLE_PREFIX . 'users';
}
http://us2.php.net/manual/en/language.oop5.static.php
Like any other PHP static variable, static properties may only be initialized using a literal or constant; expressions are not allowed. So while you may initialize a static property to an integer or array (for instance), you may not initialize it to another variable, to a function return value, or to an object.
Update for PHP >= 5.6
PHP 5.6 brought limited support for expressions:
In PHP 5.6 and later, the same rules apply as const expressions: some limited expressions are possible, provided they can be evaluated at compile time.
PHP Parse error: syntax error, unexpected '[', expecting ';' or ',' in ./dbdrivers/odbc.php IN $$args[1]
You have to specify either
${$args[1]}
or
${$args}[1]
https://www.php.net/manual/en/language.variables.variable.php
Parse error: syntax error, unexpected '=', expecting ',' or ';'
This should be
<?php
global $url = "/blog-1/index.html"; //no need of global here
if ($_SERVER['HTTP_REFERER'] == $url)
{
header('Location: /blog-2/index.html');
exit();
}
?>
if ($_SERVER['HTTP_REFERER'] == global $url) {
here global $url
is the culprit
PHP Parse error: syntax error, unexpected ':', expecting ';' or '{'
From the error it is clear that there's a problem executing your code.
PHP Parse error: syntax error, unexpected ':', expecting ';' or '{'
The problem in your case is most likely coming from PHPUnit since you have a correct php 7 setup. If PHPUnit fails to understand your code it's gonna fail in the first bit of PHP 7 code which in your case using a return type declaration
in this line
public function add(string $parameters): int {
and it's gonna be triggered in your phpunit test when you try to assert. If you comment your assersion the error should disappear.
I suggest verifiying the version of PHPUnit you are using, you should use version 5 or higher. (preferably 6 for php 7.0)
For more details about PHPunit versions, checkout this link.
How to fix Parse error: syntax error, unexpected ')', expecting '['?
Name the category variable properly
@forelse ($categories as $category)
Hope this helps
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