In_Array Multiple Values

in_array multiple values

Intersect the targets with the haystack and make sure the intersection count is equal to the target's count:

$haystack = array(...);

$target = array('foo', 'bar');

if(count(array_intersect($haystack, $target)) == count($target)){
    // all of $target is in $haystack
}

Note that you only need to verify the size of the resulting intersection is the same size as the array of target values to say that $haystack is a superset of $target.

To verify that at least one value in $target is also in $haystack, you can do this check:

 if(count(array_intersect($haystack, $target)) > 0){
     // at least one of $target is in $haystack
 }

check multiple values using in_array in PHP

You need to use array_intersect() to see what values are in both arrays. in_array() checks to see if one value exists in an array so that won't work for you (unless you use a loop to iterate through your $tempRecordTypes array and compare it to the $allRecordTypes array).

$RecordType = array_intersect($tempRecordTypes,$allRecordTypes);

PHP if in_array for multiple values

Try and see if this is helpful:

if(array_intersect($result, array('abc', '123', 'def'))) {
  $this->login_session($user);
}

How to check multiple values in an array with AND , OR operators

Your problem is happening because you only checking 1 permission as you use return in the foreach.

You should do it like this:

public static function checkPermissions($permissionLevels = []){
    $userPermission =[1,4,5,6];
    foreach($permissionLevels as $permission){
        if (!in_array($permission,$userPermission))
            return false; // if one is missing decline
    }
    return true; // if got here mean all found
}

You can also use array-intersect as:

function checkPermissions($permissionLevels = []){
        $userPermission =[1,4,5,6];
        $permissionLevels = array_unique($permissionLevels);
        return count(array_intersect($permissionLevels, $userPermission)) == count($permissionLevels));
}

Do notice to use array_unique if using the array_intersect as you can have duplicate - consider case where checkPermissions([4,4]);

Multiple values in array excluding specified key

Unset id index and then do search:

function in_array_any($needles, $haystack) {
    unset($haystack['id']);
    return !array_diff($needles, $haystack);
}

https://3v4l.org/PTjOS

PHP in_array isn't finding multiple values

You're using in_array wrong. It doesn't treat the "needle" specially. It looks for exact copies of the needle in the haystack:

php > $foo = array(1,2,3);
php > var_dump(in_array(array(1,2),$foo));
bool(false)

php > $bar = array(array(1,2),array(2,3), array(3,4));
php > var_dump(in_array(array(1,2), $bar));
bool(true)

Therefore you can't use a single in_array call to check for the existence of MULTIPLE values.

Check if one of multiple values exists in multidimensional array

Function to check existence of value in multidimensional array.

Function return true or false, you can use it in general.

function search_in_array($value, $array) {
     if(in_array($value, $array)) {
          return true;
     }
     foreach($array as $item) {
          if(is_array($item) && search_in_array($value, $item))
               return true;
     }
   return false;
}

Working example

--------- edit -----------
Based on your comment, and an example of an array

function check_in_array($value, $array, $key){
 foreach($array as $item){
  if($item[$key] == $value)
  return true;
  }
 return false;
}

And then call it like this check_in_array('orange', $array, 'FacetValueName');


Or this


check_in_array('orange', $array, 'FacetValueName') && check_in_array('Orange', $array, 'FacetValueName') && check_in_array('dark orange', $array, 'FacetValueName')


to check multiple values at once.

Working example

check multiple values exists php array

Use array_intersect

count(array_intersect($permission, $userRoles));

PHP Checking multiple values in an array - the right way?

You can do it something like this.

Solution 1:
Here we are using array_intersect for checking common values between two arrays.

<?php

ini_set('display_errors', 1);
$valuecheck = false;
$daafids=array(96,97,99,122,123,124,125,126,127,128,129,130,131,132,133);
if(count(array_intersect($prodcat, $daafids))>0)
{
    $valuecheck=true;
}

Here we are using in_array to search that particular element in the array.

Solution 2:

<?php

ini_set('display_errors', 1);
$valuecheck = false;
$daafids=array(96,97,99,122,123,124,125,126,127,128,129,130,131,132,133);
foreach ($prodcat as $daafid) {
    if(in_array($daafid,$daafids)){
       $valuecheck=true;
       break;
    }
}
if ($valuecheck == true) {
    echo $text_true;
}

check multiple values from checkbox in PHP

    <?php

if(!empty($_POST['check_list'])){
    if(
        has_values(Array(2,3,6), $_POST['check_list'])
    ){
        //Do what you need to do

    }else if(
        has_values(Array(2,3), $_POST['check_list'])
    ){
        //Do what you need to do

    }else if(
        has_values(Array(2), $_POST['check_list'])
    ){
        //Do what you need to do

    }
}else{
    //no checkboxes have been set
}

function has_values($testValues, $arrValues){
/*
    testValues is a 1 dimensional array (needles)
    arrValues is a 1 dimensional array that takes the array of set checkboxs ( haystack )
*/
    foreach ($testValues as $key => $value) {
        if(!in_array($value, $arrValues)){
            return false;
        }
    }
    return true;
}

Developer notes
in_array is not type dependent.

if a checkbox is not checked the $_POST['check_list'] index will changes

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