How to Get the Image Type in PHP

How to get the image type in php

use getimagesize() or exif_imagetype()

// integer - for example: IMAGETYPE_GIF, IMAGETYPE_JPEG etc.
$type   = exif_imagetype($_FILES['image']['tmp_name']);

and

$info   = getimagesize($_FILES['image']['tmp_name']);
$mime   = $info['mime']; // mime-type as string for ex. "image/jpeg" etc.
$width  = $info[0];      // width as integer for ex. 512
$height = $info[1];      // height as integer for ex. 384
$type   = $info[2];      // same as exif_imagetype

Mind that exif_imagetype is much faster than getimagesize. Check documentation for more info.

Get image extension

you can use image_type_to_extension function with image type returned by getimagesize:

$info = getimagesize($path);
$extension = image_type_to_extension($info[2]);

How to get image type

<input type="file" accept="image/*" id="snap" name="snap" multiple="no" title="Choose a Image file to upload" />

in you javascript

var input = $('#snap')[0];
if (input.files && input.files[0]) {
var oFile = input.files[0];
var oFile = oFile.size;
var oFileType = oFile.type

//Option 1
// check for image type (jpg and png are allowed)
var rFilter = /^(image\/jpeg|image\/png)$/i;
if (! rFilter.test(oFileType)) {
    alert('Please select a valid image file (jpg and png are allowed)');
    return;
}
//Option 2
if (!oFile.fileName.match(/\.(jpg|jpeg|png|gif)$/)){

    //TODO do your validation for image type then process ajax 
 }

}

Tutorial Link
JavaScript api doc

PHP get image file type

$_FILES merely contains the value that the browser/client specified the uploaded file to be. It is an arbitrary, user supplied value. Don't use it for anything except debugging.

getimagesize() is a function of the gd library and is maintained there. It happens to also do image type detection. The gd library is generally decent enough, but you need to have it installed.

exif_imagetype() is a function of the PHP exif extension, which does exclusively image type detection. The exif extension needs to be enabled if you want to use this function. It's also decent enough.

Choose either of the latter two, whichever seems more robust to you, offers the better features or is installed on all your systems. It's hard to give a recommendation for one or the other, in my experience they both work fine.

getting image type of remote image in php

You could do

$headers = get_headers( 'http://www.exampledomain.com/images/2?num=1' );

The $headers variable will then contain something like

Array
(
    [0] => HTTP/1.1 200 OK
    [1] => Date: Thu, 14 Oct 2010 09:46:18 GMT
    [2] => Server: Apache/2.2
    [3] => Last-Modified: Sat, 07 Feb 2009 16:31:04 GMT
    [4] => ETag: "340011c-3614-46256a9e66200"
    [5] => Accept-Ranges: bytes
    [6] => Content-Length: 13844
    [7] => Vary: User-Agent
    [8] => Expires: Thu, 15 Apr 2020 20:00:00 GMT
    [9] => Connection: close
    [10] => Content-Type: image/png
)

This will tell you whether the resource exists and what content-type (which is not necessarily also the image type) it is.

EDIT as per Pekka's comment, you still might want to determine it's mime-type after downloading. See

• How Can I Check If File Is MP3 Or Image File.

Some of the given approaches work on remote files too, so you can probably skip the get_headers pre-check altogether. Decide for yourself which one suits your needs.

How to check uploaded file type in PHP

Never use $_FILES..['type']. The information contained in it is not verified at all, it's a user-defined value. Test the type yourself. For images, exif_imagetype is usually a good choice:

$allowedTypes = array(IMAGETYPE_PNG, IMAGETYPE_JPEG, IMAGETYPE_GIF);
$detectedType = exif_imagetype($_FILES['fupload']['tmp_name']);
$error = !in_array($detectedType, $allowedTypes);

Alternatively, the finfo functions are great, if your server supports them.

Get image type from base64 encoded src string

Well you have basically two options:

1. Trust the metadata
2. Type check the image source directly

Option 1:

Probably the quicker way because it only involve splitting string, but it may be incorrect.
Something like:

$data = 'data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAA.';
$pos  = strpos($data, ';');
$type = explode(':', substr($data, 0, $pos))[1];

Option 2:

Use getimagesize() and it's equivalent for string:

$info = getimagesizefromstring(explode(',', base64_decode($data)[1], 2));
// $info['mime']; contains the mimetype

PHP : binary image data, checking the image type

The bits start with:

$JPEG = "\xFF\xD8\xFF"
$GIF  = "GIF"
$PNG  = "\x89\x50\x4e\x47\x0d\x0a\x1a\x0a"
$BMP  = "BM"
$PSD  = "8BPS"
$SWF  = "FWS"

The other ones I wouldn't know right now, but the big 3 (jpeg,gif,png) usually cover 99%. So, compare the first bytes to those string, and you have your answer.

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