Fatal error: Uncaught exception 'mysqli_sql_exception' with message 'No index used in query/prepared statement'
Take a look at this bug-report : #35450
mysqli extension reports too many warnings
Quoting a few sentences of a note :
Mysqli extension throws too many
warnings.
For example, "SELECT *
FROM table" results in a warning:
"Warning: mysqli::query(): No index
used in query/prepared statement
SELECT * FROM table ..."
And, quoting another note, which seems interesting :
Use
mysqli_report()
to disable that.
Fatal error: Uncaught mysqli_sql_exception: No index used in query/prepared statement SELECT * FROM Product
Your Product table has no column indexed, you should fix it for better performance
You can always disable this mysqli error just by adding this code
mysqli_report(MYSQLI_REPORT_INDEX);
You can find here the complet list about Enabling/Disabling the internal report functions
I suggest you to read this good article about PHP & MYSQL Communication
No index used in query/prepared statement when updating columns
Try commenting out mysqli_report(MYSQLI_REPORT_ALL);
as there are instances of it reporting too many errors, and it may be causing your code to not execute fully.
Fatal error: Uncaught exception 'mysqli_sql_exception' with message
Fatal error: Uncaught exception 'mysqli_sql_exception' with message Table 'fyp.biding' doesn't exist' in
This is as clear an error message as you'll ever get. The table biding
doesn't exists. It may be a typo in the name or your haven't created it.
PHP (v5.6) Error Uncaught exception 'mysqli_sql_exception' with message 'Access denied for user
Well I found the solution. All I had to do was to change from
$_POST[idk]
to
$_POST['idk']
Credits: Taavi Tiitsu
Then I had to delete the last 3 lines, in my case
$stmt->close(); $con->close(); ?>
You only should close PHP if you are going to write some HTML
immediately after. Other than that your PHP files should never end in
Credits: Dharman
And the last mistake was not adding the fourth parameter inside connection function (database name).
$mysqli = new mysqli($servername, $username, $password, $dbname);
You forgot to set the fourth parameter in new mysqli.
That page you linked has a $dbname variable which you are missing in
Credits: brombeer, Dharman
Related Topics
PHP Memcached Fatal Error: Class 'Memcache' Not Found
Email from PHP Has Broken Subject Header Encoding
Determining What Classes Are Defined in a PHP Class File
How to Add an Order by Clause Using Codeigniter's Active Record Methods
Php: Force File Download and Ie, Yet Again
How to Remove Square Brackets and Anything Between Them with a Regex
Check for Consecutive Dates Within a Set and Return as Range
How to Read Only 5 Last Line of the Text File in PHP
PHP Function to Get Mp3 Duration
Print Time in 15-Minute Increments Between Two Times in the Same Day
Sqlsrv_Num_Rows Not Returning Any Value
How to Override Trait Function and Call It from the Overridden Function