Day of the Week to Day Number (Monday = 1, Tuesday = 2)

day of the week to day number (Monday = 1, Tuesday = 2)

$day_of_week = date('N', strtotime('Monday'));

Convert a date to a day number (monday = 1, tuesday = 2) in R

You can do this easily with lubridate although it indexes Sunday as '1'. So since March 1, 2014 was a Saturday it would return '7'

library(lubridate)
wday(mdy("3-1-2014"))
[1] 7

How can I turn a date into the day of the week (as an integer)?

We can convert the column to str first, then to datetime and use .dt.weekday:

df = pd.DataFrame({'date': [20210101, 20210102]})
df['weekday'] = pd.to_datetime(df['date'].astype(str)).dt.weekday

df

Output:

       date  weekday
0  20210101   4     
1  20210102   5     

P.S. Here Monday = 0, ..., Sunday = 6, so if you want 1-7 instead, you can add 1 to column values

Getlocalday from Day to number

You need to incorporated our solutions into the code on your own page. Here, I am showing a sample heading that contains a span that will be updated with the day number.

window.addEventListener("DOMContentLoaded", function(){   // Get a reference to the <span> element on the page  var label = document.getElementById("day");    // Inject the answer from the function into it:  label.textContent = getLocalDay(new Date());  });
function getLocalDay(date) {  var day = date.getDay();
  var weekdays = ["Monday","Tuesday" ,"Wednesday" ,                  "Thursday" ,"Friday" ,"Saturday" ,"Sunday" ];      let dayNum = null;  weekdays.forEach(function(d, index, arry){
    if(d === weekdays[day - 1]){      dayNum = index;    }  });      return dayNum;}

<h1>The day number for today is: <span id="day"></span></h1>

Which day of the week do we receive more number of orders without counting actual number of order in particular date in excel?

You can get the max number of orders in a single formula if you're willing to make it more complex with a term for each weekday:

=MAX(SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=1)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=2)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=3)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=4)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=5)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=6)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=7)))

To get the weekday, the following might work-- it does not work in my Excel 2016 because the array in the second argument isn't recognized but the array functions have been improved in newer versions, so you could try it.

=MATCH(
MAX(
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=1)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=2)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=3)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=4)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=5)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=6)),
SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=7))
),
{
    SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=1)),
    SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=2)),
    SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=3)),
    SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=4)),
    SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=5)),
    SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=6)),
    SUMPRODUCT(--(WEEKDAY(ORDERS!C2:C16799,2)=7))
},
0)

The first part just determines the max value; the second argument of the MATCH function is an array of each of the values by weekday, the MATCH function returns the index of the matching value.

Mysql WEEKDAY() vs Mysql DayofWeek()

A relevant difference is that weekday counts the days of the week from Monday, as follows and start from 0

0=Monday, 1=Tuesday, 2=Wednesday, 3=Thursday, 4=Friday, 5=Saturday, 6=Sunday

On the other hand dayofweek counts the days of the week from Sunday and start with 1

1=Sunday, 2=Monday, 3=Tuesday, 4=Wednesday, 5=Thursday, 6=Friday, 7=Saturday

Please try

select weekday(now()) weekday, dayofweek(now()) dayofweek;

---

Related Topics