Switch from 32Bit Mode to 64 Bit (Long Mode) on 64Bit Linux

Switch from 32bit mode to 64 bit (long mode) on 64bit linux

Contrary to the other answers, I assert that in principle the short answer is YES. This is likely not supported officially in any way, but it appears to work. At the end of this answer I present a demo.

On Linux-x86_64, a 32 bit (and X32 too, according to GDB sources) process gets CS register equal to 0x23 — a selector of 32-bit ring 3 code segment defined in GDT (its base is 0). And 64 bit processes get another selector: 0x33 — a selector of long mode (i.e. 64 bit) ring 3 code segment (bases for ES, CS, SS, DS are treated unconditionally as zeros in 64 bit mode). Thus if we do far jump, far call or something similar with target segment selector of 0x33, we'll load the corresponding descriptor to the shadow part of CS and will end up in a 64 bit segment.

The demo at the bottom of this answer uses jmp far instruction to jump to 64 bit code. Note that I've chosen a special constant to load into rax, so that for 32 bit code that instruction looks like

dec eax
mov eax, 0xfafafafa
ud2
cli ; these two are unnecessary, but leaving them here for fun :)
hlt

This must fail if we execute it having 32 bit descriptor in CS shadow part (will raise SIGILL on ud2 instruction).

Now here's the demo (compile it with fasm).

format ELF executable
segment readable executable

SYS_EXIT_32BIT=1
SYS_EXIT_64BIT=60
SYS_WRITE=4
STDERR=2

entry $
mov ax,cs
cmp ax,0x23 ; 32 bit process on 64 bit kernel has this selector in CS
jne kernelIs32Bit
jmp 0x33:start64 ; switch to 64-bit segment
start64:
use64
mov rax, qword 0xf4fa0b0ffafafafa ; would crash inside this if executed as 32 bit code
xor rdi,rdi
mov eax, SYS_EXIT_64BIT
syscall
ud2

use32
kernelIs32Bit:
mov edx, msgLen
mov ecx, msg
mov ebx, STDERR
mov eax, SYS_WRITE
int 0x80
dec ebx
mov eax, SYS_EXIT_32BIT
int 0x80
msg:
db "Kernel appears to be 32 bit, can't jump to long mode segment",10
msgLen = $-msg

Is it possible to use both 64 bit and 32 bit instructions in the same executable in 64 bit Linux?

Switching between long mode and compatibility mode is done by changing CS. User mode code cannot modify the descriptor table, but it can perform a far jump or far call to a code segment that is already present in the descriptor table. I think that in Linux (for example) the required compatibility mode descriptor is present.

Here is sample code for Linux (Ubuntu). Build with

$ gcc -no-pie switch_mode.c switch_cs.s

switch_mode.c:

#include <stdlib.h>
#include <stdio.h>
#include <stdbool.h>

extern bool switch_cs(int cs, bool (*f)());
extern bool check_mode();

int main(int argc, char **argv)
{
int cs = 0x23;
if (argc > 1)
cs = strtoull(argv[1], 0, 16);
printf("switch to CS=%02x\n", cs);

bool r = switch_cs(cs, check_mode);

if (r)
printf("cs=%02x: 64-bit mode\n", cs);
else
printf("cs=%02x: 32-bit mode\n", cs);

return 0;
}

switch_cs.s:

        .intel_syntax noprefix
.code64
.text
.globl switch_cs
switch_cs:
push rbx
push rbp
mov rbp, rsp
sub rsp, 0x18

mov rbx, rsp
movq [rbx], offset .L1
mov [rbx+4], edi

// Before the lcall, switch to a stack below 4GB.
// This assumes that the data segment is below 4GB.
mov rsp, offset stack+0xf0
lcall [rbx]

// restore rsp to the original stack
leave
pop rbx
ret

.code32
.L1:
call esi
lret


.code64
.globl check_mode
// returns false for 32-bit mode; true for 64-bit mode
check_mode:
xor eax, eax
// In 32-bit mode, this instruction is executed as
// inc eax; test eax, eax
test rax, rax
setz al
ret

.data
.align 16
stack: .space 0x100

How to enter 64-bit mode on a x86_64

In order to enable 64 bit capabillities, you must switch the CPU to Long Mode.

To enter Long Mode on a 64-bit x86 processor (x86-64):

If paging is enabled, disable paging.
If CR4.PAE is not already set, set it.
Set IA32_EFER.LME = 1.
Load CR3 with a valid PML4 table.
Enable paging.
At this point you will be in compatibility mode. A far jump may be executed to switch to long mode. However, the offset must not exceed 32-bit.


Related Topics



Leave a reply



Submit