Linux Bash Script Get User Input and Store in a Array

linux bash script get user input and store in a array

read it like this:

read -a arr

Test:

read -a arr <<< "1 4 6 9 11 17 22"

print # of elements in array:

echo ${#arr[@]}

OR loop through the above array

for i in ${arr[@]}
do
   echo $i # or do whatever with individual element of the array
done

Ways of storing user input into an array in bash

The argument to read can itself be an indexed name.

for ((index=0; index < $number_of_processes; index++)); do
    i=$((index+1)) 
    read -p "Enter burst time of P$i:" 'execution[index]'
done

Bash: Get array Value by User Input

Sorry to say, but it's just a typo.

Try changing the following line:

read seleted_patch

To:

read selected_patch

Filling dynamic array with user input value

The fundamental problem is that the arrays are populated inside a pipeline. Pipeline stages are run in sub-processes so changes to variables made within them are not visible in the main program. See What happens when reading into a variable in a pipeline?.

Since the arrays are populated in the last stage of the pipeline, you can fix the problem if you are running Bash version 4.2 or later by putting

shopt -s lastpipe

in the code before the pipeline. That causes the last stage of the pipeline to be run in the top-level shell so changes to variables are visible after the pipeline completes.

Since you are using Bash, you can do what you want without using pipelines (or external commands like tr and cut). Try this Shellcheck-clean code:

#! /bin/bash -p

x="101:Redmi:Mobile:15000#102:Samsung:TV:20000#103:OnePlus:Mobile:35000#104:HP:Laptop:65000#105:Samsung:Mobile:10000#106:Samsung:TV:30000"

declare -a categ_array=()
declare -a amnt_array=()
declare -a cnt_array=()

while IFS= read -r -d '#' line || [[ -n $line ]]; do
    IFS=: read -r _ _ category amount <<<"$line"

    categ_array+=( "$category" )
    amnt_array+=( "$amount" )
    cnt_array+=( 1 )
done <<<"$x"

echo Category:
for n in "${categ_array[@]}"; do
    echo "$n"
done

Bash - Compare User input with array

I would go like this:

devices="eth0 wlan0"
input="eth0 whlan0 wlan0"

#translate output strings to array based on space
IFS='  ' read -r -a devicesa <<< "$devices"
IFS='  ' read -r -a inputa <<< "$input"

for i in "${inputa[@]}"
do
    for j in "${devicesa[@]}"; do
    if [ ${i} == ${j} ]; then
        correct=1
        break
    else
        correct=0
    fi
    done
    if [ $correct = 1 ]; then
        echo "device $i is correct"
    else
        echo "device $i isnt correct"
    fi

done

Maybe it could be more simplified, but you can read the steps to do. First go through array of strings, find devices, than compare them with user imput with writing walue about finding it. Last step is to clarify whether the value was found or not.

Bash script using getopts to store strings as an array

Would you please try the following:

#!/bin/bash

# parse the arguments before getopts
for i in "$@"; do
    if [[ $i = "-"* ]]; then
        break
    else                # append the arguments to "list" as long as it does not start with "-"
        list+=("$1")
        shift
    fi
done

while getopts :t:n: arg; do
    : your "case" code here
done

# see if the variables are properly assigned
echo "seconds=$seconds" "count=$count"
echo "list=${list[@]}"

How to take user input into an array and stop after a certain keyword?

[ "$inputs" == "done" ] && break 

Just add this and type done to exit

Example

while read inputs
do
    [ "$inputs" == "done" ] && break 
    array=("${array[@]}" $inputs)
done

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