Count Number of Files Within a Directory in Linux

Count number of files within a directory in Linux?

this is one:

ls -l . | egrep -c '^-'

Note:

ls -1 | wc -l

Which means:
ls: list files in dir

-1: (that's a ONE) only one entry per line. Change it to -1a if you want hidden files too

|: pipe output onto...

wc: "wordcount"

-l: count lines.

Recursively counting files in a Linux directory

This should work:

find DIR_NAME -type f | wc -l

Explanation:

• -type f to include only files.
• | (and not ¦) redirects find command's standard output to wc command's standard input.
• wc (short for word count) counts newlines, words and bytes on its input (docs).
• -l to count just newlines.

Notes:

• Replace DIR_NAME with . to execute the command in the current folder.
• You can also remove the -type f to include directories (and symlinks) in the count.
• It's possible this command will overcount if filenames can contain newline characters.

Explanation of why your example does not work:

In the command you showed, you do not use the "Pipe" (|) to kind-of connect two commands, but the broken bar (¦) which the shell does not recognize as a command or something similar. That's why you get that error message.

How to count number of files in each directory?

Assuming you have GNU find, let it find the directories and let bash do the rest:

find . -type d -print0 | while read -d '' -r dir; do
    files=("$dir"/*)
    printf "%5d files in directory %s\n" "${#files[@]}" "$dir"
done

Count number of files in several folders with Unix command

A possible solution using xargs is to use the -I option, which replaces occurrences of replace-str (% in the code sample below) in the initial-arguments with names read from standard input:

find . -maxdepth 1 -type d -print0 | xargs -0 -I% sh -c 'echo -n "%: "; find "%" -type f | wc -l'

You also need to pass the find command to sh if you want to pipe it with wc, otherwise wc will count files in all directories.

Another solution (maybe less cryptic) is to use a one-liner for loop:

for d in */; do echo -n "$d: "; find "$d" -type f | wc -l; done

Counting number of files in a directory with an OSX terminal command

You seem to have the right idea. I'd use -type f to find only files:

$ find some_directory -type f | wc -l

If you only want files directly under this directory and not to search recursively through subdirectories, you could add the -maxdepth flag:

$ find some_directory -maxdepth 1 -type f | wc -l

Count Files in directory and subdirectory in Linux using C

printf does not take an integer. It takes a format string and a variable list of arguments. Your problem can probably be fixed by changing:

    // Count Files
    printf(countFilesRec(argv[1]));

to

   int fileCount = countFilesRec(argv[1]);
   printf("File count = %d\n", fileCount);

The change stores the integer result of your function in a variable and then uses a suitable format string to print it.

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