Match Exact String

Regular expression for exact match of a string

if you have a the input password in a variable and you want to match exactly 123456 then anchors will help you:

/^123456$/

in perl the test for matching the password would be something like

print "MATCH_OK" if ($input_pass=~/^123456$/);

EDIT:

bart kiers is right tho, why don't you use a strcmp() for this? every language has it in its own way

as a second thought, you may want to consider a safer authentication mechanism :)

Match exact string

Use the start and end delimiters: ^abc$

How to match exact word with regex python?

You can use a negative lookbehind and a negative lookahead pattern to ensure that each matching keyword is neither preceded nor followed by a non-space character:

(?<!\S)(?:c|java)(?!\S)

Demo: https://regex101.com/r/GOF8Uo/3

Alternatively, simply split the given string into a list of words and test if any word is in the set of keywords you're looking for:

def match(x):
    return any(w in {'c', 'java'} for w in x.split())

Regular Expression to Match String Exactly?

use ^ and $ to match the start and end of your string

^[0-9]{6}$
^[0-9]{6}\.[0-9]{3}$

Reference: http://www.regular-expressions.info/anchors.html

Also, as noted by Mikael Svenson, you can use the word boundary \b if you are searching for this pattern in a larger chunk of text.

Reference: http://www.regular-expressions.info/wordboundaries.html

You could also write both those regexes in one shot

^\d{6}(\.\d{3})?$

Matching exact string with JavaScript

Either modify the pattern beforehand so that it only matches the entire string:

var r = /^a$/

or check afterward whether the pattern matched the whole string:

function matchExact(r, str) {
   var match = str.match(r);
   return match && str === match[0];
}

Check string matches exact format swift 5

You need two things:

Escape parentheses
Add anchors because in the current code, the regex can match a part of a string.

You can thus use

stringToCheck.range(of: #"^\([0-9],[0-9]\)\z"#, options: .regularExpression, range: nil, locale: nil) != nil

Note the # chars on both ends, they allow escaping with single backslashes.

Details:

^ - start of string
\( - a ( char
[0-9] - a single ASCII digit (add + after ] to match one or more digits)
, - a comma
[0-9] - a single ASCII digit (add + after ] to match one or more digits)
\) - a ) char
\z - the very end of string (if linebreaks cannot be present in the string, $ is enough).