How to Get Character Array from a String

Converting String to Character array in Java

Use this:

String str = "testString";
char[] charArray = str.toCharArray();
Character[] charObjectArray = ArrayUtils.toObject(charArray);

How to search a string in a char array in C?

if the chararray contains stringend or do not end with \0 you can use these code, because strstr will brake on these ones:

#include <stdio.h>
int main()
{
    char c_to_search[5] = "asdf";

    char text[68] = "hello my name is \0 there is some other string behind it \n\0 asdf";

    int pos_search = 0;
    int pos_text = 0;
    int len_search = 4;
    int len_text = 67;
    for (pos_text = 0; pos_text < len_text - len_search;++pos_text)
    {
        if(text[pos_text] == c_to_search[pos_search])
        {
            ++pos_search;
            if(pos_search == len_search)
            {
                // match
                printf("match from %d to %d\n",pos_text-len_search,pos_text);
                return;
            }
        }
        else
        {
           pos_text -=pos_search;
           pos_search = 0;
        }
    }
    // no match
    printf("no match\n");
   return 0;
}

http://ideone.com/2In3mr

How to get character array from a string?

Note: This is not unicode compliant. "IU".split('') results in the
4 character array ["I", "�", "�", "u"] which can lead to dangerous
bugs. See answers below for safe alternatives.

Just split it by an empty string.

var output = "Hello world!".split('');console.log(output);

Convert String to Character Array? and Retrieve

This appears to be a homework question, so I'm only going to give hints.

1) How would I convert it to a charterer array?

You've already done that!! However:

it would possibly be better if either you used a char[] instead of a Character[], and
if you do continue to use a Character, then it is better to use Character.valueOf(...) instead of new Character(...).

2) once converted how do I retrieve each and individual letter 1 by 1?

Use a for loop. It is one of the standard Java statements. Refer to your Java textbook, tutorial, lecture notes ...

... how would i output it in an edit text box... using outputbox.setText(????)

Use static Character.toString(char), or Character.toString() to create a String, depending on the type you have used. You can then pass that as an argument to setText ...

For details of the methods I mentioned above, read the javadocs.

How to access individual characters of an array of strings correctly?

%s is used for printing strings. An individual character is not a string, it's a char, you print it with %c.

You also don't use & when passing arguments to printf() (unless you're trying to print a pointer to a variable rather than the variable itself).

for (int i = 0; i < 3; i++)
{
    strcpy(a[i], ch[i]);
    printf("a[%d]: \"%s\"\n", i, a[i]);
    for (int j = 0; j < 5; j++)
        printf("a[%d][%d]: \"%c\"\n", i, j, a[i][j]);
    }
}

How to create char array of letters from a string array ? (C#)

You can do this:

var foo = "Nice to meet you";
var fooArr = s.ToCharArray();
HashSet<char> set = new();
set.UnionWith(fooArr);

//or if you want without whitespaces you could refactor this as below
set.UnionWith(fooArr.Where(c => c != ' '));

UPDATE:
You could even make an extension method:

public static IEnumerable<char> ToUniqueCharArray(this string source, char? ignoreChar)
{
     var charArray = source.ToCharArray();
     HashSet<char> set = new();
     set.UnionWith(charArray.Where(c => c != ignoreChar));
     return set;
}

And then you can use it as:

var foo = "Nice to meet you";
var uniqueChars = foo.ToUniqueCharArray(ignoreChar: ' ');

// if you want to keep the whitespace
var uniqueChars = foo.ToUniqueCharArray(ignoreChar: null);

How to search String array through char array?

You can sort char array and then compare it using Arrays.equal. By sorting char array, there will be no need to use 2 for loops.

import java.util.Arrays;
import java.util.Scanner;

public class Bug {

        public static void main(String[] args) {
            String strArray[]=new String[4];
            char chrArray[]=new char[4];
            Scanner input = new Scanner(System.in);
            System.out.println("Enter the words :");
            for(int i=0;i<strArray.length;i++){
                strArray[i]=input.next();

            }
            System.out.println("Enter the Characters :");
            for (int i = 0; i < chrArray.length; i++) {
                chrArray[i]=input.next().charAt(0);

            }
            Arrays.sort(chrArray);

            for (int i = 0; i < strArray.length; i++) {
                char[] x = strArray[i].toCharArray();
                Arrays.sort(x);
                if(Arrays.equals(chrArray, x))
                {
                    System.out.println(strArray[i]);
                    break;
                }
            }
        }

 }

How to create a string array from a char array

Convert your char array to a string:
```
Dim s = new String(x)
```
Split the string on vbNullChar. (We use vbNullChar(0) to convert the single-character string vbNullChar into a char. You can also use Chr(0) or ChrW(0) instead.):
```
Dim channelNames = s.Split(vbNullChar(0))
```

_{(All my code examples assume Option Strict On and Option Infer On).}

How to convert a string to character array in c (or) how to extract a single char form string?

In C, a string is actually stored as an array of characters, so the 'string pointer' is pointing to the first character. For instance,

char myString[] = "This is some text";

You can access any character as a simple char by using myString as an array, thus:

char myChar = myString[6];
printf("%c\n", myChar); // Prints s

Hope this helps!
David

Changing an element of an array of char[]

When trying to apply the same concept with an array of character arrays, you can't change the values

Yes you can, just not the way you are doing it. You can't assign one array to another. But you can use strcpy() instead to copy characters from one array to another, eg:

strcpy(stuff[i], "Not Cool");

Or better, strncpy(), eg:

strncpy(stuff[i], "Not Cool", 20);