How to Find If an Array Contains a Specific String in JavaScript/Jquery

How to find if an array contains a specific string in JavaScript/jQuery?

You really don't need jQuery for this.

var myarr = ["I", "like", "turtles"];
var arraycontainsturtles = (myarr.indexOf("turtles") > -1);

Hint: indexOf returns a number, representing the position where the specified searchvalue occurs for the first time, or -1 if it never
occurs

or

function arrayContains(needle, arrhaystack)
{
    return (arrhaystack.indexOf(needle) > -1);
}

It's worth noting that array.indexOf(..) is not supported in IE < 9, but jQuery's indexOf(...) function will work even for those older versions.

Jquery check if array contains substring

You can use regexp to find the right price:

var regions = ["city1", "city2", "city3"];var address = "example address 42-200 City1 Poland";var address2 = "city3";var address3 = "city6";
function priceForAddress(address, regions) {  var city = regions.find(function (region) {    var reg = new RegExp(region, 'i');    return address.match(reg) !== null;  });    if (city) {    return '20$';  } else {    return '4$/km';  }}
console.log(priceForAddress(address, regions));console.log(priceForAddress(address2, regions));console.log(priceForAddress(address3, regions));

How can one check if an array contains a substring?

The Array.prototype has very useful .filter function for your purpose.

const arr = ['positive', 'positron', 'negative', 'negatron'];
function findMatches() {  let searchVal = document.getElementById('test').value;  let res = arr.filter(el => el.indexOf(searchVal) > -1);  document.getElementById('result').innerHTML = res.join(', ');}

<input type="text" id="test" /><button type="button" onclick="findMatches()">Find</button><br /> Array: ['positive', 'positron', 'negative', 'negatron']<br /><span id="result"></span>

How to check array if it contains a string with same text?

You can use array#filter with string#includes to check for substring in your array of string.

var cards = ["ace_of_clubs.png","2_of_clubs.png","3_of_clubs.png","ace_of_hearts.png"],    f_string = cards.filter(card => card.includes("clubs"));console.log(f_string);

Check if an array of strings contains a substring

Because includes will compare '#' with each array element.

Let's try with some or find if you want to find if you want to get exactly element

var array = ["123", "456", "#123"];
var el = array.find(a =>a.includes("#"));
console.log(el)

How to find part of a string in array jQuery

Seeing that OP changed his original question: http://jsfiddle.net/c4qPX/2/ is a solution for both of them (there's no really difference for the algorithm if we're searching through the array of searched keys or searched values) - the point is what to compare.

var array1 = ['BA11', 'BA14', 'BA15'];
var array2 = ['GL156', 'GL24', 'GL31'];
var search = 'GL156DC';

$.each([array1, array2], function(index, value){
    $.each(value, function(key, cell){
        if (search.indexOf(cell) !== -1)
            console.log('found in array '+index, cell);
    });
});

How to check if a string contains text from an array of substrings in JavaScript?

There's nothing built-in that will do that for you, you'll have to write a function for it, although it can be just a callback to the some array method.

Two approaches for you:

• Array some method
• Regular expression

Array some

The array some method (added in ES5) makes this quite straightforward:

if (substrings.some(function(v) { return str.indexOf(v) >= 0; })) {
    // There's at least one
}

Even better with an arrow function and the newish includes method (both ES2015+):

if (substrings.some(v => str.includes(v))) {
    // There's at least one
}

Live Example:

const substrings = ["one", "two", "three"];
let str;

// Setup
console.log(`Substrings: ${substrings}`);

// Try it where we expect a match
str = "this has one";
if (substrings.some(v => str.includes(v))) {
    console.log(`Match using "${str}"`);
} else {
    console.log(`No match using "${str}"`);
}

// Try it where we DON'T expect a match
str = "this doesn't have any";
if (substrings.some(v => str.includes(v))) {
    console.log(`Match using "${str}"`);
} else {
    console.log(`No match using "${str}"`);
}

Unable to determine if a string contains a word from an array

Change inArray function with array.some(text => itag.textContent.includes(text)).

Declare all variables via var or const or let.

Instead of innerHTML use textContent. This will not try to parse the content
and will work faster.

var array = ["Hello", "Goodbye"];
var a = document.getElementsByClassName("here");
for (var i = 0; i < a.length; i++) {    var itag = a[i].getElementsByTagName("i")[0];    var textContent = itag.textContent;    if(array.some(text => textContent.includes(text))) {       console.log(textContent);    }}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script><div class="here"><i><a href="link.php">Hello</a> | <a href="link2.php">Example</a></i></div>
<div class="here"><i><a href="link.php">Hey</a> | <a href="link2.php">Hello</a></i></div>

How do I check if an array includes a value in JavaScript?

Modern browsers have Array#includes, which does exactly that and is widely supported by everyone except IE:

console.log(['joe', 'jane', 'mary'].includes('jane')); //true

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