Understand Arraylist Indexoutofboundsexception in Android

Understand Arraylist IndexOutOfBoundsException in Android

java.util.ArrayList.throwIndexOutOfBoundsException: Invalid index 3,
size is 3

It means you have ArrayList which having 3 elements where you can get each element like 0,1,2 positions. And you are trying to read 4th element which does not exists into ArrayList.

java.util.ArrayList.throwIndexOutOfBoundsException: Invalid index 0,
size is 0

It means you have a empty ArrayList, and you are trying to read 1st element.

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ArrayIndexOutOfBoundsException - Examples

An array-index out of bounds exception is a Java exception thrown due to the fact that the program is trying to access an
element at a position that is outside an array limit, hence the words "Out of bounds". In other words, the program is trying to
access an element at an index that is outside the array bounds. To understand array bounds, let us consider the following diagram:

The picture above contains an array that consists of 7 elements. Each element in the array has its own index/position. In Java, an index always starts with
0 and ends with the length of the array -1. For example, the array above consists of 7 elements, therefore it's indices start from 0 and end with 6 (7-1). Attempting
to access an element with an index less than 0 or more than 6 will cause Java to throw an ArrayIndexOutOfBoundsException.

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Read more about ArrayIndexOutOfBoundsException - Examples, Causes & Fixes

IndexOutOfBoundsException with Android ArrayList

i<sortedFridayTimes.size()+1

You are looping past the last element in the array. Why the +1?

If there are N elements in the array, then the elements are from indexes 0 through to N-1.

So it should be:

for(int i=0; i<sortedFridayTimes.size(); i++) {

java.lang.IndexOutOfBoundsException: Index: 7, Size: 7. Why is this happening?

Index begins from 0. Therefore, for an array of size 7, the index will be from 0 to 6.

• If the index is 0, then it refers to the 1st element of the array.
• If the index is 1, then it refers to the 2nd element.
• ...

The error

java.lang.IndexOutOfBoundsException: Index: 7, Size: 7

signifies that

The array has only 7 elements, but an attempt was made to extract the 8th element.

Android java.lang.IndexOutOfBoundsException error

Inside your method onClick(), it has a reference to your "i" variable, and its last value is 29, which is when it breaks from your loop, so when you call
alfabeharfler.get(i), its using the value 29 in all your calls, not just when you click on button B, and because of this you got that exception "IndexOutOfBoundsException".

Try declaring a new final variable inside your loop and use that inside your onClick method, something like this (I haven't tried this code, but it should work):

for(i = 0; i < alfabebutonlar.size(); i++){
    final int index = i;
    alfabebutonlar.get(index).setOnClickListener ( new View.OnClickListener () {
        public void onClick(View alfabebutonv){

            startActivity(getIntent().putExtra("harf", alfabeharfler.get(index)));

        }
    });

}

Hope this helps.

java.lang.IndexOutOfBoundsException: Index: 1, Size: 0 at java.util.ArrayList.get(ArrayList.java:437)

SharedPreferences uses String keys, not int. When you are reading or writing to SharedPreferences with string literal "i", you are not indexing the items how you think you are. You are storing a single value and probably over writing it several times.

IndexOutOfBoundsException when adding to ArrayList at index

ArrayList index starts from 0(Zero)

Your array list size is 0, and you are adding String element at 1st index. Without adding element at 0th index you can't add next index positions. Which is wrong.

So, Simply make it as

 s.add("Elephant");

Or you can

s.add(0,"Elephant");

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