Pass Array to Method Java

pass array to method Java

You do this:

private void PassArray() {
String[] arrayw = new String[4]; //populate array
PrintA(arrayw);
}

private void PrintA(String[] a) {
//do whatever with array here
}

Just pass it as any other variable.

In Java, arrays are passed by reference.

Passing arrays in java

Your code looks OK. You just need to assign the result of fillArray() to a variable, in order to use this result for further methods.

It would look like:

 int[] array = fillArray();
System.out.println("Sum=" + sumArray(array));
System.out.println("Average=" + avgArray(array));
printArray(array);

Pass array to method and return the array

You should write a method like this:

public static int[] doubleArray (int[] array) {
//double the array... I think you know how to do this part.
return array;
}

Now lets say you have an array called myArray and you can pass it into the method like this:

doubleArray (myArray);

And then the elements in myArray will be doubled. You can also use the return value of the method for some other uses.

Alternatively, you can return another brand new array:

public static int[] doubleArray (int[] array) {
int[] newArray = new int[array.length];
//put all the stuff in "array" in "newArray"
//double the new array... I think you know how to do this part.
return newArray;
}

Then when you called the method, the argument passed in will not be changed. But the return value has the doubled array.

Passing array to a method (Java)

Well it's not clear where you'd get the values to pass in from, but here's how you would declare the method:

public static void replaceArrayElement(String[] name, int index, String value)

You'd call it with:

// Get the values from elsewhere, obviously
replaceArrayElement(array, 5, "fred");

Note that I've used String[] name instead of String name[] - while the latter syntax is permitted, it's strongly discouraged as a matter of style.

How to input arrays into a method

no but you can print integer arrays,

int[] numArray = {1,2,3,4,5,6,7,8};
Test2.number(numArray);

if you want to insert numbers instead of arrays change:

public static int[] numbers (int[] numbers){
}

to

public static int numbers (int numbers){

}

if you have any further problems please reply to this answer

How to pass variable array in JAVA

What about?

printer(Arrays.asList(new int[]{x, y, z}));

Java: How to pass the array data to a method?

First define method like

public void studentInfo(){
System.out.println("Student name: "+this.getName());
System.out.println("Gender: "+this.getGender());
System.out.println("Student number: "+this.getStudNumber());

System.out.println("Program: "+this.getProgram());
System.out.println("Year Level: "+this.getYrlevel());
System.out.println("Organization: "+this.getOrg());
}

in Student class. Then you may use anywhere you need:

Stream.of(s1).forEach(Student::studentInfo)

Where s1 is your students array.

How to pass an Array and the current index to a method in Java

Arrays are just like any other type. If you want to pass an array to a method, declare a parameter of that type, e.g.

private static void swap(int[] ar, int i, int j) { ... }
^ This is a parameter of type int[].

Note that the i and j you pass should be indexes, not values in the array:

swap(ar, i, j);

and swap the elements thus:

temp = ar[i];
ar[i] = ar[j];
ar[j] = temp;

Are arrays passed by value or passed by reference in Java?

Your question is based on a false premise.

Arrays are not a primitive type in Java, but they are not objects either ... "

In fact, all arrays in Java are objects1. Every Java array type has java.lang.Object as its supertype, and inherits the implementation of all methods in the Object API.

... so are they passed by value or by reference? Does it depend on what the array contains, for example references or a primitive type?

Short answers: 1) pass by value, and 2) it makes no difference.

Longer answer:

Like all Java objects, arrays are passed by value ... but the value is the reference to the array. So, when you assign something to a cell of the array in the called method, you will be assigning to the same array object that the caller sees.

This is NOT pass-by-reference. Real pass-by-reference involves passing the address of a variable. With real pass-by-reference, the called method can assign to its local variable, and this causes the variable in the caller to be updated.

But not in Java. In Java, the called method can update the contents of the array, and it can update its copy of the array reference, but it can't update the variable in the caller that holds the caller's array reference. Hence ... what Java is providing is NOT pass-by-reference.

Here are some links that explain the difference between pass-by-reference and pass-by-value. If you don't understand my explanations above, or if you feel inclined to disagree with the terminology, you should read them.

  • http://publib.boulder.ibm.com/infocenter/comphelp/v8v101/topic/com.ibm.xlcpp8a.doc/language/ref/cplr233.htm
  • http://www.cs.fsu.edu/~myers/c++/notes/references.html

Related SO question:

  • Is Java "pass-by-reference" or "pass-by-value"?

Historical background:

The phrase "pass-by-reference" was originally "call-by-reference", and it was used to distinguish the argument passing semantics of FORTRAN (call-by-reference) from those of ALGOL-60 (call-by-value and call-by-name).

  • In call-by-value, the argument expression is evaluated to a value, and that value is copied to the called method.

  • In call-by-reference, the argument expression is partially evaluated to an "lvalue" (i.e. the address of a variable or array element) that is passed to the calling method. The calling method can then directly read and update the variable / element.

  • In call-by-name, the actual argument expression is passed to the calling method (!!) which can evaluate it multiple times (!!!). This was complicated to implement, and could be used (abused) to write code that was very difficult to understand. Call-by-name was only ever used in Algol-60 (thankfully!).

UPDATE

Actually, Algol-60's call-by-name is similar to passing lambda expressions as parameters. The wrinkle is that these not-exactly-lambda-expressions (they were referred to as "thunks" at the implementation level) can indirectly modify the state of variables that are in scope in the calling procedure / function. That is part of what made them so hard to understand. (See the Wikipedia page on Jensen's Device for example.)


1. Nothing in the linked Q&A (Arrays in Java and how they are stored in memory) either states or implies that arrays are not objects.



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