Pass a Local File in to Url in Java

Pass a local file in to URL in Java

new File(path).toURI().toURL();

URL wont open file:\C filepath in Java

file:/C:/ is not a valid file url. Try starting your URLs with file://C:/.

Additionally, the File(String) constructor does not take a URL, it takes a local file path. If you have a URL as a string that you want to parse, use the URL(String) constructor:

URL fileURL = new URL("file://C:/RAdev/Basic/src/test/resources/xml Data/test dir/app-config-seed-data.xml");
is = fileURL.openStream();

Creating a URL object with a relative path

The solution is to find an absolute path to url1.html make an object of java.io.File on it, and then use toURI().toURL() combination:

URL url1 = (new java.io.File(absolutePathToHTMLFile)).toURI().toURL();

Assuming if the current directory is the root of page, you can pass a relative path to File:

URL url1 = (new java.io.File("page/url1.html")).toURI().toURL();

or

URL url1 = (new java.io.File(new java.io.File("page"), "url1.html")).toURI().toURL();

But this will depend on where you run the application from. I would make it taking the root directory as a command-line argument if it is the only configurable option for the app, or from a configuration file, if it has one.

The another solution is to put the html file as a resource into the jar file of your application.

How to give url path in spring boot refer to local file

Try this

URL url = Thread.currentThread().getContextClassLoader().getResource("wsdl/outbound.wsdl");

This should work

How can I download and save a file from the Internet using Java?

Give Java NIO a try:

URL website = new URL("http://www.website.com/information.asp");
ReadableByteChannel rbc = Channels.newChannel(website.openStream());
FileOutputStream fos = new FileOutputStream("information.html");
fos.getChannel().transferFrom(rbc, 0, Long.MAX_VALUE);

Using transferFrom() is potentially much more efficient than a simple loop that reads from the source channel and writes to this channel. Many operating systems can transfer bytes directly from the source channel into the filesystem cache without actually copying them.

Check more about it here.

Note: The third parameter in transferFrom is the maximum number of bytes to transfer. Integer.MAX_VALUE will transfer at most 2^31 bytes, Long.MAX_VALUE will allow at most 2^63 bytes (larger than any file in existence).

How to upload remote file to the POST URL in java?

Not 100% what you mean by "without downloading to the local machine."

Here's how to avoid downloading the file into a temporary local file and then uploading that.
The basic approach is to read from one URLConnection (instead of the local file) and write to another URLConnection (like you do already).
Start by doing the request to sourceString, so

HttpsURLConnection source = (HttpsURLConnection) new URL("https://machine.B/path/to/file.zip").openConnection();

then keep everything until youset the Content-Length and replace that with

conn.setRequestProperty("Content-Length", source.getContentLength());

and then all you have to do is use

InputStream is = source.getInputStream();

instead of your diskis.

PS: I don't get the purpose of the .available logic, why not just use CHUNK_LEN for the buffer size?
PPS: also the while(i<0) loop can be removed ;-)

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