Maven: How to Change Path to Target Directory from Command Line

Maven: How to change path to target directory from command line?

You should use profiles.

<profiles>
    <profile>
        <id>otherOutputDir</id>
        <build>
            <directory>yourDirectory</directory>
        </build>
    </profile>
</profiles>

And start maven with your profile

mvn compile -PotherOutputDir

If you really want to define your directory from the command line you could do something like this (NOT recommended at all) :

<properties>
    <buildDirectory>${project.basedir}/target</buildDirectory>
</properties>

<build>
    <directory>${buildDirectory}</directory>
</build>

And compile like this :

mvn compile -DbuildDirectory=test

That's because you can't change the target directory by using -Dproject.build.directory

Change output directory for maven2

In file / settings / build. Execution, Deployment / Compiler there is a point AnnotationProcessors this is where the target folder was being created from.
By turning this off, since i wasnt using it, i got the wanted output when building.

How to run Maven from another directory (without cd to project dir)?

You can use the parameter -f (or --file) and specify the path to your pom file, e.g. mvn -f /path/to/pom.xml

This runs maven "as if" it were in /path/to for the working directory.

Use alternate name for Maven target

The target folder is very important, ¿why you want to rename it? If isn't really necessary, in think that you shouldn't rename it.

I found 2 related posts (this and this). If it helpt to you, only add to your pom:

<build>
<directory>/yourDirectory/.target</directory>
</build>

You can put it into a profile too. Hope it has been helpful.

Maven: specify the outputDirectory only for packaging a jar?

on command line

-DoutputDirectory=<path>

and in pom.xml

<build>
  <plugins>
    <plugin>
      <groupId>org.apache.maven.plugins</groupId>
      <artifactId>maven-jar-plugin</artifactId>
      <version>2.3.1</version>
      <configuration>
        <outputDirectory>/my/path</outputDirectory>
      </configuration>
    </plugin>
  </plugins>
</build>

Maven project.build.directory

You can find those maven properties in the super pom.

You find the jar here:

${M2_HOME}/lib/maven-model-builder-3.0.3.jar

Open the jar with 7-zip or some other archiver (or use the jar tool).

Navigate to

org/apache/maven/model

There you'll find the pom-4.0.0.xml.

It contains all those "short cuts":

<project>
    ...
    <build>
        <directory>${project.basedir}/target</directory>
        <outputDirectory>${project.build.directory}/classes</outputDirectory>
        <finalName>${project.artifactId}-${project.version}</finalName>
        <testOutputDirectory>${project.build.directory}/test-classes</testOutputDirectory>
        <sourceDirectory>${project.basedir}/src/main/java</sourceDirectory>
        <scriptSourceDirectory>src/main/scripts</scriptSourceDirectory>
        <testSourceDirectory>${project.basedir}/src/test/java</testSourceDirectory>
        <resources>
            <resource>
                <directory>${project.basedir}/src/main/resources</directory>
            </resource>
        </resources>
        <testResources>
            <testResource>
                <directory>${project.basedir}/src/test/resources</directory>
            </testResource>
        </testResources>
        ...
    </build>
    ...
</project>

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Update

After some lobbying I am adding a link to the pom-4.0.0.xml. This allows you to see the properties without opening up the local jar file.

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