How to Get Parameters from the Url with Jsp

How to get parameters from the URL with JSP

In a GET request, the request parameters are taken from the query string (the data following the question mark on the URL). For example, the URL http://hostname.com?p1=v1&p2=v2 contains two request parameters - - p1 and p2. In a POST request, the request parameters are taken from both query string and the posted data which is encoded in the body of the request.

This example demonstrates how to include the value of a request parameter in the generated output:

Hello <b><%= request.getParameter("name") %></b>!

If the page was accessed with the URL:

http://hostname.com/mywebapp/mypage.jsp?name=John+Smith

the resulting output would be:

Hello <b>John Smith</b>!

If name is not specified on the query string, the output would be:

Hello <b>null</b>!

This example uses the value of a query parameter in a scriptlet:

<%
    if (request.getParameter("name") == null) {
        out.println("Please enter your name.");
    } else {
        out.println("Hello <b>"+request. getParameter("name")+"</b>!");
    }
%>

how to get full path of URL including multiple parameters in jsp

I think this is what you are looking for..

String str=request.getRequestURL()+"?";
Enumeration<String> paramNames = request.getParameterNames();
while (paramNames.hasMoreElements())
{
    String paramName = paramNames.nextElement();
    String[] paramValues = request.getParameterValues(paramName);
    for (int i = 0; i < paramValues.length; i++) 
    {
        String paramValue = paramValues[i];
        str=str + paramName + "=" + paramValue;
    }
    str=str+"&";
}
System.out.println(str.substring(0,str.length()-1));    //remove the last character from String

Get parameters dynamically from URL in JSP

URLSearchParams is supported by a majority of browser

const url = new URL('https://example.com?q0=aaa&q1=bbb&q2=ccc&q4=ddd')
const params = new URLSearchParams(url.search.slice(1))
params.get('q0') // expect "aaa"
params.get('q1') // expect "bbb"
params.get('q2') // expect "ccc"
params.get('q5') // expect null because q5 doesn't exist

Look at the documentation for more methods.

Get value from a parameter in URL in JSP

This is a String value, so you need to use:

if (("1").equals(cat))

How to get parameters value as it is from the URL with JSP

Try encoding params like this:

class Ideone
{
    public static void main (String[] args) throws java.lang.Exception
    {
        String param = "P+q+EvhE951eg/I5nz1vi/w2YpJdH+v/vSPaQNg/I=";
        System.out.printf("Orginal Param: %s\n", param);
        param = java.net.URLEncoder.encode(param, "utf-8");
        System.out.printf("Encoded Param: %s\n", param);
    }
}

Output:

Orginal Param: P+q+EvhE951eg/I5nz1vi/w2YpJdH+v/vSPaQNg/I=
Encoded Param: P%2Bq%2BEvhE951eg%2FI5nz1vi%2Fw2YpJdH%2Bv%2FvSPaQNg%2FI%3D

How to hide the passing params in url using jsp page

The response of Joseph in the comments is completely right.

If you want to replace your <a href link... > that send a Get request, you have to replace it by a <form> + your destination url in the ‘action’ attribute and your parameters as hidden input field.

Here is the direct link to such an example:

https://stackoverflow.com/a/8398954/4444956

And replace the action attribute value with “generatekey.jsp” and the ‘d’ and ‘d2’ as input hidden fields (with their corresponding ds... value).

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