How do you create a Spring JPA repository findBy query using a property that contains a keyword?
To overcome this problem, I've defined the query manually using the @Query
annotation. I'll happily accept anyone else's answer if they find a solution that doesn't require a manual query.
public interface ThingRepository extends JpaRepository<ThingEntity, Long> {
@Query("SELECT t FROM Thing t WHERE t.fooIn = ?1 AND t.bar = ?2")
ThingEntity findByFooInAndBar(String fooIn, String bar);
}
Spring Data JPA repository method with property name containing a special word
A workaround is to rename the Java field to avoid special words, while preserving the column name using the @Column
annotation.
@Column(name = "nameOrId")
public String nameId;
The JPA method is renamed accordingly.
MyObj findByNameId(String nameOrId);
How can I search a keyword in entity's list?
So, you want to find a single Product, containing keyword? But findByKeywordsContaining can potentially find several Products. So return type should be List<Product>
.
If you want to return Optional<Product>
, then your method should be called something like findFirstByKeywordsContaining
Here's a query, Hibernate makes
select
product0_.id as id1_1_,
product0_.price as price2_1_,
product0_.title as title3_1_
from
products product0_
where
? in (
select
keywords1_.keywords
from
product_keywords keywords1_
where
product0_.id=keywords1_.product_id
)
;
The query is ok and if you substitute ? for a keyword, it gives right results. But Spring substitutes it for %keyword% (surrounded with percent sign) and it doesn't work of course.
There's another way to what you want.
public interface ProductRepository extends JpaRepository<Product, Long> {
List<Product> findByKeywordsIn(List<String> keywords);
}
This forms an sql query, which actually gets results, even though you have to provide list of keywords, instead of a single keyword
Hibernate generates another query for that
select
product0_.id as id1_1_,
product0_.price as price2_1_,
product0_.title as title3_1_
from
products product0_
left outer join product_keywords keywords1_
on product0_.id=keywords1_.product_id
where
keywords1_.keywords in (?)
And Spring passeds an array to ? parameter, so everything works.
As far as I understand, both queries are roughly equivalent, because RDBMS engine should optimize them to the same execution plan. But it depends on RMBMS implementation and indices.
Query by Boolean properties in spring-data-jpa without using method parameters
The JPA repository section query creation has the following methods.
True findByActiveTrue() … where x.active = true
False findByActiveFalse() … where x.active = false
My guess would be to use
@Query
public Iterable<Entity> findByEnabledTrue();
spring boot CrudRepository findby function could not mapped
This is a tough one, I would highly suggest that you adhere to standard Java conventions such as starting all of your field names with a lower case letter (camelCase format). I believe that is the reason that it is not able to find the field.
You will want it to look like this in the Repository
`List<HolidaySchedule> findByHDay(String hDay);`
and
@Column(name="HSD_DAY")
private String hDay;
in your model.
Start with this and see where it gets you.
See below for Spring Reference
https://docs.spring.io/spring-data/jpa/docs/1.11.6.RELEASE/reference/html/#jpa.query-methods.query-creation
Spring CrudRepository findByInventoryIds(List<Long> inventoryIdList) - equivalent to IN clause
findByInventoryIdIn(List<Long> inventoryIdList)
should do the trick.
The HTTP request parameter format would be like so:
Yes ?id=1,2,3
No ?id=1&id=2&id=3
The complete list of JPA repository keywords can be found in the current documentation listing. It shows that IsIn
is equivalent – if you prefer the verb for readability – and that JPA also supports NotIn
and IsNotIn
.
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