Type 'Any' Has No Subscript Members (Firebase)

Type 'Any' has no subscript members (firebase)

snapshot.value has the type Any?, so you need to cast it to the underlying type before you can subscript it. Since snapshot.value!.dynamicType is NSDictionary, use an optional cast as? NSDictionary to establish the type, and then you can access the value in the dictionary:

if let dict = snapshot.value as? NSDictionary, postContent = dict["content"] as? String {
    content = postContent
} else {
    content = ""
}

Or, you can do it as a one-liner:

content = (snapshot.value as? NSDictionary)?["content"] as? String ?? ""

type 'Any?' has no subscript members (using Firebase)

Two issues.

1. Optionals

This is Swift's way of making a variable be in one of two states namely, have a value or be nil. A variable can only be in one of these states. You make a variable an optional by adding a question mark in front of it.

2. Any

By declaring a variable to be of type Any, this means you're not explicitly stating its type during declaration. Firebase makes all of its returns be of type Any in order to give us developers the option of fiddling with the data as we so please hence less constraints on our side.

snapshot.value is of type Any but Firebase always returns a JSON tree and JSON trees can be represented as Dictionaries. So what should we do?

Since snapshot.value is an optional, we should check first to see if its nil.
If not nil, convert it to a dictionary then start accessing the respective elements inside it.

The code below does the job for you and I've added comments to explain what's happening.

ref?.child("Users").child(username).observeSingleEvent(of: .value, with:
{ (snapshot) in

    // This does two things.
    // It first checks to see if snapshot.value is nil. If it is nil, then it goes inside the else statement then prints out the statement and stops execution.
    // If it isn't nil though, it converts it into a dictionary that maps a String as its key and the value of type AnyObject then stores this dictionary into the variable firebaseResponse.

    // I used [String:Any] because this will handle all types of data types. So your data can be Int, String, Double and even Arrays.
    guard let firebaseResponse = snapshot.value as? [String:Any] else
    {
        print("Snapshot is nil hence no data returned")
        return
    }

    // At this point we just convert the respective element back to its proper data type i.e from AnyObject to say String or Int etc

    let userName = firebaseResponse["Username"] as! String

    self.usernameField.text = username     
})

type 'Any' has no subscript members

snapshot.value has a type of Any. A subscript is a special kind of function that uses the syntax of enclosing a value in braces. This subscript function is implemented by Dictionary.

So what is happening here is that YOU as the developer know that snapshot.value is a Dictionary, but the compiler doesn't. It won't let you call the subscript function because you are trying to call it on a value of type Any and Any does not implement subscript. In order to do this, you have to tell the compiler that your snapshot.value is actually a Dictionary. Further more Dictionary lets you use the subscript function with values of whatever type the Dictionary's keys are. So you need to tell it you have a Dictionary with keys as String(AKA [String: Any]). Going even further than that, in your case, you seem to know that all of the values in your Dictionary are String as well, so instead of casting each value after you subscript it to String using as! String, if you just tell it that your Dictionary has keys and values that are both String types (AKA [String: String]), then you will be able to subscript to access the values and the compiler will know the values are String also!

guard let snapshotDict = snapshot.value as? [String: String] else {
    // Do something to handle the error 
    // if your snapshot.value isn't the type you thought it was going to be. 
}

let employerName = snapshotDict["employerName"]
let employerImage = snapshotDict["employerImage"]
let uid = snapshotDict["fid"]

And there you have it!

Type 'Any' has no subscript members after updating to Swift 3

In FIRDataSnapshot, value is of type id.

In Swift 3, id is imported as Any.

In the Firebase documentation, it says value can be any of NSDictionary, NSArray, NSNumber, or NSString -- clearly, subscripting doesn't make sense on all of these, especially in Swift. If you know it's an NSDictionary in your case, then you should cast it to that.

Type 'Any' has no subscript members when accessing dictionary in UserDefaults

The reason of showing this error in your code is: the compiler cannot recognize result as dictionary, if you tried to option and click on result you would see that its type is Any. You have to cast it first as [String: AnyObject] and then get "Authorities" form it.

It should be like this:

if let result = UserDefaults.standard.dictionary(forKey: "dict") {
    print(result)
}

That's how you should "optional binding" the dictionary, thus (assumeing that "Authorities" is a [String: String]):

if let addresses = result["Authorities"] as? [String: String] {
    print(addresses)
}

You could also do it as one step:

if let result = UserDefaults.standard.dictionary(forKey: "dict"),
   let addresses = result["Authorities"] as? [String: String] {
    print(result)
    print(addresses)

    let levelAccess = addresses["levelAccess"]
    print(levelAccess) // optional
}

Finally, you could get the levelAcess from addresses as:

let levelAccess = addresses["levelAccess"]

Again, note that levelAccess would be an optional string (String?), which means you should also handle it.

Type 'Any?' has no subscript members

change this

 let email = result["email"] as? String

into

  guard let resultNew = result as? [String:Any] 

 let email = resultNew["email"]  as! String

full answer

let parameters = ["fields": "email, first_name, last_name,  picture.type(large)"]
    FBSDKGraphRequest(graphPath: "me", parameters: parameters).start { (connection, result, error) in

        guard let resultNew = result as? [String:Any] 

       let email = resultNew["email"]  as! String
    }