How to Split String into Substrings on iOS

How to split string into substrings on iOS?

You can also split a string by a substring, using NString's componentsSeparatedByString method.

Example from documentation:

NSString *list = @"Norman, Stanley, Fletcher";
NSArray *listItems = [list componentsSeparatedByString:@", "];

Split string by particular character ,iOS

NSString *str=@"Description#Data#IMG";  //is your str

NSArray *items = [str componentsSeparatedByString:@"#"];   //take the one array for split the string

NSString *str1=[items objectAtIndex:0];   //shows Description
NSString *str2=[items objectAtIndex:1];   //Shows Data
NSString *str3=[items objectAtIndex:2];   // shows IMG

Finally NSLog(@"your  3 stirs ==%@   %@  %@", str1, str2, str3);

Swift

 //is your str  
 var str: String = "Description#Data#IMG"

let items = String.components(separatedBy: "#") //take the one array for split the string
var str1: String = items.objectAtIndex(0)    //shows Description
var str2: String = items.objectAtIndex(1)    //Shows Data
var str3: String = items.objectAtIndex(2) // shows IMG

option-2

let items = str.characters.split("#")
var str1: String  =  String(items.first!)
var str1: String  =  String(items.last!)

option 3

// An example string separated by commas.
let line = "apple,peach,kiwi"

// Use components() to split the string.
// ... Split on comma chars.
let parts = line.components(separatedBy: ",")

// Result has 3 strings.
print(parts.count)
print(parts)

Split a String into an array in Swift?

The Swift way is to use the global split function, like so:

var fullName = "First Last"
var fullNameArr = split(fullName) {$0 == " "}
var firstName: String = fullNameArr[0]
var lastName: String? = fullNameArr.count > 1 ? fullNameArr[1] : nil

with Swift 2

In Swift 2 the use of split becomes a bit more complicated due to the introduction of the internal CharacterView type. This means that String no longer adopts the SequenceType or CollectionType protocols and you must instead use the .characters property to access a CharacterView type representation of a String instance. (Note: CharacterView does adopt SequenceType and CollectionType protocols).

let fullName = "First Last"
let fullNameArr = fullName.characters.split{$0 == " "}.map(String.init)
// or simply:
// let fullNameArr = fullName.characters.split{" "}.map(String.init)

fullNameArr[0] // First
fullNameArr[1] // Last 

How can split from string to array by chunks of given size

You can group your collection elements (in this case Characters) every n elements as follow:

extension Collection {
    func unfoldSubSequences(limitedTo maxLength: Int) -> UnfoldSequence<SubSequence,Index> {
        sequence(state: startIndex) { start in
            guard start < self.endIndex else { return nil }
            let end = self.index(start, offsetBy: maxLength, limitedBy: self.endIndex) ?? self.endIndex
            defer { start = end }
            return self[start..<end]
        }
    }
    func subSequences(of n: Int) -> [SubSequence] {
        .init(unfoldSubSequences(limitedTo: n))
    }
}

---

let numbers = "1234567"
let subSequences = numbers.subSequences(of: 2)
print(subSequences)    // ["12", "34", "56", "7"]

edit/update:

If you would like to append the exceeding characters to the last group:

extension Collection {
    func unfoldSubSequencesWithTail(lenght: Int) -> UnfoldSequence<SubSequence,Index> {
        let n = count / lenght
        var counter = 0
        return sequence(state: startIndex) { start in
            guard start < endIndex else { return nil }
            let end = index(start, offsetBy: lenght, limitedBy: endIndex) ?? endIndex
            counter += 1
            if counter == n {
                defer { start = endIndex }
                return self[start...]
            } else {
                defer { start = end }
                return self[start..<end]
            }
        }
    }
    func subSequencesWithTail(n: Int) -> [SubSequence] {
        .init(unfoldSubSequencesWithTail(lenght: n))
    }
}

---

let numbers = "1234567"
let subSequencesWithTail = numbers.subSequencesWithTail(n: 2)
print(subSequencesWithTail)    // ["12", "34", "567"]

Split a String into an array in Swift?

The Swift way is to use the global split function, like so:

var fullName = "First Last"
var fullNameArr = split(fullName) {$0 == " "}
var firstName: String = fullNameArr[0]
var lastName: String? = fullNameArr.count > 1 ? fullNameArr[1] : nil

with Swift 2

In Swift 2 the use of split becomes a bit more complicated due to the introduction of the internal CharacterView type. This means that String no longer adopts the SequenceType or CollectionType protocols and you must instead use the .characters property to access a CharacterView type representation of a String instance. (Note: CharacterView does adopt SequenceType and CollectionType protocols).

let fullName = "First Last"
let fullNameArr = fullName.characters.split{$0 == " "}.map(String.init)
// or simply:
// let fullNameArr = fullName.characters.split{" "}.map(String.init)

fullNameArr[0] // First
fullNameArr[1] // Last 

How to split strings into substring start with some characters in ios

I would just use rangeOfString: to locate the next 43, take the 20 characters from there on with substringWithRange:, and start over with the remaining substring (substringFromIndex:).

NSString *str = @"43 01 08 43 13 01 18 FD 48 6B D1 43 01 22 02 01 02 02 F1 48 6B D1 43 02 03 03 51 03 52 75 48 6B D1 43 03 53 11 08 15 52 9D 48 6B D1 43 16 14 16 32 00 00";
NSMutableArray *substrings = [NSMutableArray array];
NSRange range = { .length = 20 };
while ((range.location = [str rangeOfString:@"43"].location) != NSNotFound
       && str.length >= range.length + range.location) {
    [substrings addObject:[str substringWithRange:range]];
    str = [str substringFromIndex:range.location + range.length];
}

Swift: How to split a string and then extract specific substring?

There is a solution below, it will extract any string between brackets into an array without brackets, it also gives you string without element as word as an array element:

var myString = "exampleString ( 123 ) "

//creates result array from String by separating elements by space
var result = myString.split(separator: " ")

//filters array to remove '(' and ')'
result = result.filter { $0 != "(" && $0 != ")" }

print(result)

Then if you want to build a String back from result array with string elements, do the following:

var resultString = result.joined(separator: " ")

print(resultString)

Might not be ideal, but it might be useful for you.

How to split the string from an array of strings in swift

you can use flatMap:

let dates = ["2018/06/25 05:32:30","2018/05/25 02:37","2018/04/25 05:32:50","2018/07/25 06:30:30"]
let times = dates.flatMap({ $0.split(separator: " ").last ?? nil })
print(times)
// prints: ["05:32:30", "02:37", "05:32:50", "06:30:30"]

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