HTML.Beginform() with an Absolute Url

Using Custom paths or absolute URI with Html.BeginForm()

BeginForm method with single parameter is used to generate a relative path from routedata that is provided within parameter variable. Which means, that you are setting URI parameter with name action and giving it and value http://absolute.com, therefor value is going to be encoded.

What you want to use is overload where it asks you for htmlAttributes.

This will not encode value for action attribute:

@using (Html.BeginForm(
     null, null, FormMethod.Post,
     new {@action="http://absolute.com/submit/example"}
)){}
// the result is:
<form action="http://absolute.com/submit/example" method="post"> 
</form>

UPDATE: method show below will not utilize JavaScript client-side validation.

since, you don't really need the helper to figure out the path of the form. You can use the html and set action of the form manually.

Validation will still work, if you are using helpers for the input fields.

<form action="http://absolute.com/submit/example" method="post">    
    @Html.LabelFor(model => model.Example)
    @Html.ValidationMessageFor(model => model.Example, "*")
    @Html.TextAreaFor(model => model.Example, 8, 60, null)
</form>

Best way to create form with Html.BeginForm() that should be SSL?

You can override the action attribute of the form created by Html.BeginForm.

<% 
   var actionURL = (Model.UseSSL ? "https://" : "http://") 
                   + Request.Url.Host + Request.Url.PathAndQuery;    

   using (
          Html.BeginForm(
                         "Action", 
                         "Controller", 
                         FormMethod.Post, 
                         new { @action = actionURL }
                        )
         )
%>

Note the use of the Model.UseSSL flag, which should be passed to this View by its Controller.

t4Mvc and Html.BeginForm with split controller and action name

Please try:

Html.BeginForm(MVC.EmailTemplate.Save())

Getting Absolute URL from an ASP.NET MVC Action

You can do it by the following:

var urlBuilder =
    new System.UriBuilder(Request.Url.AbsoluteUri)
        {
            Path = Url.Action("Action", "Controller"),
            Query = null,
        };

Uri uri = urlBuilder.Uri;
string url = urlBuilder.ToString();
// or urlBuilder.Uri.ToString()

Instead of Url.Action() in this sample, you can also use Url.Content(), or any routing method, or really just pass a path.

But if the URL does go to a Controller Action, there is a more compact way:

var contactUsUriString =
    Url.Action("Contact-Us", "About",
               routeValues: null /* specify if needed */,
               protocol: Request.Url.Scheme /* This is the trick */);

The trick here is that once you specify the protocol/scheme when calling any routing method, you get an absolute URL. I recommend this one when possible, but you also have the more generic way in the first example in case you need it.

I have blogged about it in details here:

http://gurustop.net/blog/2012/03/23/writing-absolute-urls-to-other-actions-in-asp-net-mvc/

Extracted from Meligy’s AngularJS & Web Dev Goodies Newsletter

Cannot assign attributes to form using Html.BeginForm

Your current code is matching with the below overload of BeginForm method

public static MvcForm BeginForm(
    this HtmlHelper htmlHelper,
    string actionName,
    string controllerName,
    object routeValues
)

The third parameter here is an object for the route values. These will be added as the querystring key value(s) to your form's action attribute value. That is the reason you are seeing those big url as the action attribute value.

If you want to specify the html attributes( Id,class etc), Use this overload which has a fourth parameter which takes the html attributes. The third parameter is the FormMethod.

public static MvcForm BeginForm(
    this HtmlHelper htmlHelper,
    string actionName,
    string controllerName,
    FormMethod method,
    object htmlAttributes
)

This should work.

@using (Html.BeginForm("Create", "Post",FormMethod.Post, 
       new { @id = "MaintenanceForm", @class = "datatable", @nonvalidate = "nonvalidate" }))
{

}

Replace Create and Post with your action method name and controller name.

Html.BeginForm does not redirect to action Method

Your Code should be like this then it will work

@using (Html.BeginForm("SubmitEmp","Client",FormMethod.Post))

We cannot and use full controller name like ClientController for specifying controller name we need to specify only the name of Client

In your URL localhost:5000/ClientController/Submitemp showing controller name ClientController it should be Client only change your URL like localhost:5000/Client/Submitemp then it will work.

Cheers!!

Rewriting Html.BeginForm() in MVC 3.0 and keeping unobtrusive javascript

The answer to your underlying question (i.e. how to use BeginForm/EndForm syntax) is to do it in the following manner:

@{ Html.BeginForm(...); }
<div> content</div>
@{ Html.EndForm(); }

Unfortunately the Razor syntax right now is a bit more verbose when invoking helpers that write to the output (as opposed to the majority of helpers which just return an html snippet). You could probably make this easier by writing your own extension methods like so:

public static IHtmlString FormBegin(this HtmlHelper helper, ...) {
    helper.BeginForm(...);
    return new HtmlString("");
}

public static IHtmlString FormEnd(this HtmlHelper helper) {
    helper.EndForm();
    return new HtmlString("");
}