Write Bytes to File

How to write bytes to file?

If you want to write bytes then you should open the file in binary mode.

f = open('/tmp/output', 'wb')

Write bytes to file

If I understand you correctly, this should do the trick. You'll need add using System.IO at the top of your file if you don't already have it.

public bool ByteArrayToFile(string fileName, byte[] byteArray)
{
try
{
using (var fs = new FileStream(fileName, FileMode.Create, FileAccess.Write))
{
fs.Write(byteArray, 0, byteArray.Length);
return true;
}
}
catch (Exception ex)
{
Console.WriteLine("Exception caught in process: {0}", ex);
return false;
}
}

Write bytes to a file natively in PowerShell

Running C# assemblies is native to PowerShell, therefore you are already writing bytes to a file "natively".

If you insist, you can use a construction like set-content test.jpg -value (([char[]]$decoded) -join ""), this has a drawback of adding #13#10 to the end of written data. With JPEGs it's bearable, but other files may get corrupt from this alteration. So please stick with byte-optimized routines of .NET instead of searching for "native" approaches - these are already native.

C++ writing byte to file

operator << is designed for formatted output.

When writing strict binary, you should focus on member functions put (for one byte) or write (for a variable number of bytes).

This will write your bitset as a single byte.

binFile.put( a.to_ulong() );

How to write bytes to a file in Python 3 without knowing the encoding?

It's a matter of using APIs that operate on bytes, rather than strings.

sys.stdout.buffer.write(bytes_)

As the docs explain, you can also detach the streams, so they're binary by default.

This accesses the underlying byte buffer.

tempfile.TemporaryFile().write(bytes_)

This is already a byte API.

open('filename', 'wb').write(bytes_)

As you would expect from the 'b', this is a byte API.

from io import BytesIO
BytesIO().write(bytes_)

BytesIO is the byte equivalent to StringIO.

EDIT: write will Just Work on any binary file-like object. So the general solution is just to find the right API.

How to write byte(s) to a file in C++?

The issue is operator<< is the text encoding method, even if you've specified std::ofstream::binary. You can use put to write a single binary character or write to output multiple characters. Note that you are responsible for the conversion of data to its char representation.

std::bitset<8> bits = foo();
std::ofstream outfile("compressed", std::ofstream::out | std::ofstream::binary);

// In reality, your conversion code is probably more complicated than this
char repr = bits.to_ulong();

// Use scoped sentries to output with put/write
{
std::ofstream::sentry sentry(outfile);
if (sentry)
{
outfile.put(repr); // <- Option 1
outfile.write(&repr, sizeof repr); // <- Option 2
}
}

Python how to write bytes in a .txt file

You need to convert \n to bytes.

file.write(encrypted_data + bytes('\n'))

cannot write bytes to gif file (python)

I am going to take a guess that you are attempting to directly call the functions and have not created an object from your class and then called the functions via your object. Following is a snippet of code I wrote using your class and functions that did pump out data to a binary file.

import pathlib

class fileAdd():
def create_file(self, input):
self.filepath = pathlib.Path('gifs/' + input)
self.fp = open(self.filepath, 'ab')
print("file created")
def add_data(self, input):
self.fp.write(input)
print("adding data")
def close(self):
self.fp.close()

x = b'\x00\x00\x00'

fpx = fileAdd()

fpx.create_file("GIF")

fpx.add_data(x)

fpx.close()

Following is the sample output to the file called "GIF".

@Una:~/Python_Programs/File/gifs$ hexdump GIF
0000000 6548 6c6c 006f 0000
0000008

Give that a try and see if that moves you forward.

byte[] to file in Java

Use Apache Commons IO

FileUtils.writeByteArrayToFile(new File("pathname"), myByteArray)

Or, if you insist on making work for yourself...

try (FileOutputStream fos = new FileOutputStream("pathname")) {
fos.write(myByteArray);
//fos.close(); There is no more need for this line since you had created the instance of "fos" inside the try. And this will automatically close the OutputStream
}


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