How to fix the error, Invalid expression term 'else'?
The following is valid C# code:
if (Password == RealPassword) ;
This is valid syntax for a single-line if
. The single expression inside the if
just happens to be an empty expression (i.e. ;
).
The following is also valid C# code:
{
Console.WriteLine("Correct Login");
}
The brackets form a section of grouped code. The brackets themselves do nothing in this case, but this is a possible way to organize your code into visual collapsible groups. (If you're using Visual Studio, though, the recommended way is to use #region XXX
and #endregion
.)
The following, however, is not valid C# code:
else ;
Because the previous if
was terminated by the empty expression and was then followed by other code, this else
is left orphaned. That is an error, which causes your program not to compile.
To get your desired result, remove the semicolons from after your if
and else
statements.
C# compiler throws invalid arguments error. Why?
In .NET, there is a distinct concept between reference types and value types.
A reference type is an object that is allocated on the heap (It will be a subclass of System.Object). All that is on the stack is a pointer to this object. Because of that, it is perfectly valid to store a null pointer.
A value type is an object that is allocated on the stack, it will be a subclass of System.ValueType. Because a value type lives on the stack, when you pass its value to a function, you pass the entire contents of the object.
Value types cannot be null.
Most C# primitive types are value types. String is a special type of primitive that is actually a reference type.
In .NET 2.0, MS added the ability to enclose a generic type inside of a struct so that it could simulate a nullable type. What really happens is that the logic inside of the Nullable<T> struct is emulating a null for you.
They expressed it using a syntax shortcut by adding a question mark to the type, for example:
int? nullableInt = null;
float? nullableFloat = null;
etc...
If you don't like the int? syntax, you can always use Nullable<SomeType>
public String getBar(Int32 a, String b, Nullable<Int32> c)
As a side note, I prefer to add an overload when doing what you are doing, just to make the syntax nicer.
public String getBar(Int32 a, String b)
{
this.getBar(a,b,null);
}
public String getBar(Int32 a, String b, Nullable<Int32> c)
{
}
Invalid IL code generated
I fixed my own problem. As multiple individuals correctly pointed out in the comments, the IL is correct. The issue wasn't related to my code or the generated IL, but to the decompiler, dotPeek.
What happend was the following: I generated the DLL for the first time, but the IL was wrong (it had 2 return statements), decompiled it with dotPeek and saw that the IL was malformed. I did this again but with the correct IL (only 1 return statement) and deleted the old DLL, renamed the new DLL to the old, deleted, one. DotPeek however did not like this, it would show me the updated IL, but not the updated code.
After many restarts and removing/re-adding the assembly I found out this was the case. dnSpy seems to work much better than dotPeek so I'll be using that in the future.
C# return isn't letting user know of invalid entry
It's because your method is asking for a return. But since you have an if, let's put it this way
Team Leader: Hey bob I want you to finish this job.
In here you are expecting that bob will finish your job but you put a condition
You: If I can go to office today sir.
since you have an If condition, what if you can't go today? Does it mean you can't finish the job tomorrow and any other day? That's why it says not all code paths return a value because you never gave other/default value
Going back in your code, you ask
if (isTrue == true)
{
result = num1 + num2;
Console.WriteLine("Adding your number and a random number, please wait...");
Thread.Sleep(1000);
Console.WriteLine("{0} + {1} = {2}", num1, num2, result);
isTrue = true;
return result.ToString();
}
but what if it is not true, then it will go to else. You can set int result = 0 so it is defined from start when else run and it will not return an error of unassigned local variable.
public string myMethod()
{
int result = 0; //This must have a default value so in else part it is not unassigned when you return.
int num2 = RandomNumberInt();
bool isTrue = int.TryParse(userInputString, out int num1);
if(isTrue)
{
//do something in result here
return result.toString(); //This will return your in value as string
}
else
{
return "Your message as string" // This will return any string to provide for string return of the method
}
}
Your problem regarding not displaying the string "Please enter a valid number" is a different issue. You have to post also what method calls the AddNumbers method that will use the returned string. For use the problem is in that method because your if and else is in correct format;
How to refactor this decompiled C# code with invalid reference syntax?
This is one of those things that dotPeek fails on but ILSpy handles nicely. What you're seeing is a compiler optimization of the +=
operator. Rather than calculate the field location twice - once to fetch the value and again to store it - the compiler generates code that calculates the field offset one time then uses it for both parts of the operation.
The bit you're having trouble with (the unknown ^
operator) is most likely an attempt by dotPeek to show a dereference of the ref variable. Of course this isn't necessary in C# where we just use the name of the variable itself.
Just rewrite it as:
m_position += byteCount;
The compiler will decide whether or not it wants to add that particular optimization in.
C# Invalid expression term '+='
you create new variable with in your for loop that the reason
if you need to store data each loop you should create variable outside loop
like this
string point_value = "";
for(int i=0; i < dataGridView1.Rows.Count; i++)
{
point_value += dataGridView1.Rows[i].Cells[1].Value + "|";
}
for more information about loop pattern here
(edited to avoid empty value and out of range from DiplomacyNotWar's commented)
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