How to Upload File Using Ajax.Beginform() Asynchronously

Not able to upload file using Ajax.BeginForm() asynchronously

You cannot upload files using AJAX. This is not supported. If you want to do that you could either use some file upload plugin such as Uploadify or Blueimp File Upload or use the HTML 5 File API if the client browser supports it.

Ajax.BeginForm in MVC to upload files

That is complicated better use jquery forms plugin.

Here is the sample:

Html.BeginForm

 @using (Html.BeginForm("YourAction", "YourController"))
{
    @Html.AntiForgeryToken()
    <input type="file" name="files"><br>
    <input type="submit" value="Upload File to Server">
}

Action Method

    [HttpPost]
    [ValidateAntiForgeryToken]
    public void YourAction(IEnumerable<HttpPostedFileBase> files)
    {
        if (files != null)
        {
            foreach (var file in files)
            {
                // Verify that the user selected a file
                if (file != null && file.ContentLength > 0)
                {
                    // extract only the fielname
                    var fileName = Path.GetFileName(file.FileName);
                    // TODO: need to define destination
                    var path = Path.Combine(Server.MapPath("~/Upload"), fileName);
                    file.SaveAs(path);
                }
            }
        }
    }

Progress Bar

<div class="progress progress-striped">
   <div class="progress-bar progress-bar-success">0%</div>
</div>

Jquery & Form script

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>

<script>
(function() {

var bar = $('.progress-bar');
var percent = $('.progress-bar');
var status = $('#status');

$('form').ajaxForm({
    beforeSend: function() {
        status.empty();
        var percentVal = '0%';
        bar.width(percentVal)
        percent.html(percentVal);
    },
    uploadProgress: function(event, position, total, percentComplete) {
        var percentVal = percentComplete + '%';
        bar.width(percentVal)
        percent.html(percentVal);
    },
    success: function() {
        var percentVal = '100%';
        bar.width(percentVal)
        percent.html(percentVal);
    },
    complete: function(xhr) {
        status.html(xhr.responseText);
    }
}); 

})();       
</script>

Update...

People who are getting issue of calling action method twice is due to Ajax.BeginForm, just convert it to Html.BeginForm(). For more clarification and to download sample code please refer at this blog.

Ajax.BeginForm does not work asynchronous

when this happens its almost always because your script files aren't loaded, see below post :

http://completedevelopment.blogspot.com/2011/02/unobstrusive-javascript-in-mvc-3-helps.html

Set the mentioned flag in the web.config:

1. Include a reference to the jQuery library ~/Scripts/jquery-1.4.4.js

2. Include a reference to the library that hooks this magic at ~/Scripts/jquery.unobtrusive-ajax.js

   
   
   
   
   

Uploading both data and files in one form using Ajax?

The problem I had was using the wrong jQuery identifier.

You can upload data and files with one form using ajax.

PHP + HTML

<?php

print_r($_POST);
print_r($_FILES);
?>

<form id="data" method="post" enctype="multipart/form-data">
    <input type="text" name="first" value="Bob" />
    <input type="text" name="middle" value="James" />
    <input type="text" name="last" value="Smith" />
    <input name="image" type="file" />
    <button>Submit</button>
</form>

jQuery + Ajax

$("form#data").submit(function(e) {
    e.preventDefault();    
    var formData = new FormData(this);

    $.ajax({
        url: window.location.pathname,
        type: 'POST',
        data: formData,
        success: function (data) {
            alert(data)
        },
        cache: false,
        contentType: false,
        processData: false
    });
});

Short Version

$("form#data").submit(function(e) {
    e.preventDefault();
    var formData = new FormData(this);    

    $.post($(this).attr("action"), formData, function(data) {
        alert(data);
    });
});

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