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How can I avoid SQL injection attacks?

The proper way to avoid SQL Injection attacks is NOT to simply disallow certain problematic characters, but rather to use parameterized SQL. In short, parameterized SQL prevents the database from executing raw user input as part of the SQL command this prevents user input like "drop table" from being executed. Just escaping characters does not stop all forms of SQL injection attacks and excluding certain words such as "Drop" does not work in all cases; there can be certain fields where "Drop" is a perfectly valid part of the data entry.

You can find some good articles on the subject of paramaterized SQL here:

https://blog.codinghorror.com/give-me-parameterized-sql-or-give-me-death/

http://www.codeproject.com/KB/database/ParameterizingAdHocSQL.aspx

Now that you mentioned that you are working with ASP.net I can give you some links that deal specifically with SQL Injection in ASP.

https://dzone.com/articles/aspnet-preventing-sql-injectio
https://www.c-sharpcorner.com/UploadFile/75a48f/how-sql-injection-can-be-possible-in-asp-net-websites/

Here is a more general article on making your ASP more secure:
http://www.codeproject.com/KB/web-security/Securing_ASP_NET_Apps.aspx

And, of course the MSDN article on SQL injection:
http://msdn.microsoft.com/en-us/library/ms998271.aspx

What are good ways to prevent SQL injection?

By using the SqlCommand and its child collection of parameters all the pain of checking for sql injection is taken away from you and will be handled by these classes.

Here is an example, taken from one of the articles above:

private static void UpdateDemographics(Int32 customerID,
    string demoXml, string connectionString)
{
    // Update the demographics for a store, which is stored  
    // in an xml column.  
    string commandText = "UPDATE Sales.Store SET Demographics = @demographics "
        + "WHERE CustomerID = @ID;";

    using (SqlConnection connection = new SqlConnection(connectionString))
    {
        SqlCommand command = new SqlCommand(commandText, connection);
        command.Parameters.Add("@ID", SqlDbType.Int);
        command.Parameters["@ID"].Value = customerID;

        // Use AddWithValue to assign Demographics. 
        // SQL Server will implicitly convert strings into XML.
        command.Parameters.AddWithValue("@demographics", demoXml);

        try
        {
            connection.Open();
            Int32 rowsAffected = command.ExecuteNonQuery();
            Console.WriteLine("RowsAffected: {0}", rowsAffected);
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex.Message);
        }
    }
}

How can prepared statements protect from SQL injection attacks?

The idea is very simple - the query and the data are sent to the database server separately.

That's all.

The root of the SQL injection problem is in the mixing of the code and the data.

In fact, our SQL query is a legitimate program.
And we are creating such a program dynamically, adding some data on the fly. Thus, the data may interfere with the program code and even alter it, as every SQL injection example shows it (all examples in PHP/Mysql):

$expected_data = 1;
$query = "SELECT * FROM users where id=$expected_data";

will produce a regular query

SELECT * FROM users where id=1

while this code

$spoiled_data = "1; DROP TABLE users;"
$query        = "SELECT * FROM users where id=$spoiled_data";

will produce a malicious sequence

SELECT * FROM users where id=1; DROP TABLE users;

It works because we are adding the data directly to the program body and it becomes a part of the program, so the data may alter the program, and depending on the data passed, we will either have a regular output or a table users deleted.

While in case of prepared statements we don't alter our program, it remains intact
That's the point.

We are sending a program to the server first

$db->prepare("SELECT * FROM users where id=?");

where the data is substituted by some variable called a parameter or a placeholder.

Note that exactly the same query is sent to the server, without any data in it! And then we're sending the data with the second request, essentially separated from the query itself:

$db->execute($data);

so it can't alter our program and do any harm.

Quite simple - isn't it?

The only thing I have to add that always omitted in the every manual:

Prepared statements can protect only data literals, but cannot be used with any other query part.

So, once we have to add, say, a dynamical identifier - a field name, for example - prepared statements can't help us. I've explained the matter recently, so I won't repeat myself.

Prevention of SQL Injection Attacks

For the code given - yes, it is pretty safe and impenetrable.

However, your idea of defending from SQL injection is quite wrong in general.

There is no "stripping of SQL special characters" in your code. And there is no point in such a stripping at all.

Speaking of SQL strings, they are pretty safe if properly formatted. But for all other SQL literals, the thing you call "stripping" will actually strip nothing.

How can I prevent SQL injection in PHP?

The correct way to avoid SQL injection attacks, no matter which database you use, is to separate the data from SQL, so that data stays data and will never be interpreted as commands by the SQL parser. It is possible to create an SQL statement with correctly formatted data parts, but if you don't fully understand the details, you should always use prepared statements and parameterized queries. These are SQL statements that are sent to and parsed by the database server separately from any parameters. This way it is impossible for an attacker to inject malicious SQL.

You basically have two options to achieve this:

1. Using PDO (for any supported database driver):

   $stmt = $pdo->prepare('SELECT * FROM employees WHERE name = :name');
   $stmt->execute([ 'name' => $name ]);
   
   foreach ($stmt as $row) {
       // Do something with $row
   }
   

2. Using MySQLi (for MySQL):

Since PHP 8.2+ we can make use of execute_query() which prepares, binds parameters, and executes SQL statement in one method:

$result = $dbConnection->execute_query('SELECT * FROM employees WHERE name = ?', [$name]);

while ($row = $result->fetch_assoc()) {
    // Do something with $row
}

Up to PHP8.1:

$stmt = $dbConnection->prepare('SELECT * FROM employees WHERE name = ?');
$stmt->bind_param('s', $name); // 's' specifies the variable type => 'string'
$stmt->execute();

$result = $stmt->get_result();
while ($row = $result->fetch_assoc()) {
    // Do something with $row
}

If you're connecting to a database other than MySQL, there is a driver-specific second option that you can refer to (for example, pg_prepare() and pg_execute() for PostgreSQL). PDO is the universal option.

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Correctly setting up the connection

PDO

Note that when using PDO to access a MySQL database real prepared statements are not used by default. To fix this you have to disable the emulation of prepared statements. An example of creating a connection using PDO is:

$dbConnection = new PDO('mysql:dbname=dbtest;host=127.0.0.1;charset=utf8mb4', 'user', 'password');

$dbConnection->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$dbConnection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

In the above example, the error mode isn't strictly necessary, but it is advised to add it. This way PDO will inform you of all MySQL errors by means of throwing the PDOException.

What is mandatory, however, is the first setAttribute() line, which tells PDO to disable emulated prepared statements and use real prepared statements. This makes sure the statement and the values aren't parsed by PHP before sending it to the MySQL server (giving a possible attacker no chance to inject malicious SQL).

Although you can set the charset in the options of the constructor, it's important to note that 'older' versions of PHP (before 5.3.6) silently ignored the charset parameter in the DSN.

Mysqli

For mysqli we have to follow the same routine:

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); // error reporting
$dbConnection = new mysqli('127.0.0.1', 'username', 'password', 'test');
$dbConnection->set_charset('utf8mb4'); // charset

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Explanation

The SQL statement you pass to prepare is parsed and compiled by the database server. By specifying parameters (either a ? or a named parameter like :name in the example above) you tell the database engine where you want to filter on. Then when you call execute, the prepared statement is combined with the parameter values you specify.

The important thing here is that the parameter values are combined with the compiled statement, not an SQL string. SQL injection works by tricking the script into including malicious strings when it creates SQL to send to the database. So by sending the actual SQL separately from the parameters, you limit the risk of ending up with something you didn't intend.

Any parameters you send when using a prepared statement will just be treated as strings (although the database engine may do some optimization so parameters may end up as numbers too, of course). In the example above, if the $name variable contains 'Sarah'; DELETE FROM employees the result would simply be a search for the string "'Sarah'; DELETE FROM employees", and you will not end up with an empty table.

Another benefit of using prepared statements is that if you execute the same statement many times in the same session it will only be parsed and compiled once, giving you some speed gains.

Oh, and since you asked about how to do it for an insert, here's an example (using PDO):

$preparedStatement = $db->prepare('INSERT INTO table (column) VALUES (:column)');

$preparedStatement->execute([ 'column' => $unsafeValue ]);

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Can prepared statements be used for dynamic queries?

While you can still use prepared statements for the query parameters, the structure of the dynamic query itself cannot be parametrized and certain query features cannot be parametrized.

For these specific scenarios, the best thing to do is use a whitelist filter that restricts the possible values.

// Value whitelist
// $dir can only be 'DESC', otherwise it will be 'ASC'
if (empty($dir) || $dir !== 'DESC') {
   $dir = 'ASC';
}

Avoiding an Sql injection attack

Always use command parameters to avoid sql injection. Sql injections are handled by Command Parameter automatically. You don't need to worry about sql injection if you use command parameters.

When you don't use command parameters, the parameters' values are simply inserted in sql query without handling sql injection. But when you use command parameters, ADO.Net handles sql injection for you.

Prevent SQL injection attack in PHP

SQLite3::exec is for executing a query string, not a prepared statement. You need to use SQLite3Stmt::execute instead. Change:

if (!$db->exec ($sql)) {
    throw new Exception($db->lastErrorMsg());
}

to

if (!$sql->execute()) {
    throw new Exception($db->lastErrorMsg());
}

Note you can't echo $sql as it is an object, not a simple type. If you want to look at what a SQLite3Stmt object looks like, you would need to print_r($sql) or var_dump($sql).

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