Getting Path Relative to the Current Working Directory

Getting path relative to the current working directory?

If you don't mind the slashes being switched, you could [ab]use Uri:

Uri file = new Uri(@"c:\foo\bar\blop\blap.txt");
// Must end in a slash to indicate folder
Uri folder = new Uri(@"c:\foo\bar\");
string relativePath = 
Uri.UnescapeDataString(
    folder.MakeRelativeUri(file)
        .ToString()
        .Replace('/', Path.DirectorySeparatorChar)
    );

As a function/method:

string GetRelativePath(string filespec, string folder)
{
    Uri pathUri = new Uri(filespec);
    // Folders must end in a slash
    if (!folder.EndsWith(Path.DirectorySeparatorChar.ToString()))
    {
        folder += Path.DirectorySeparatorChar;
    }
    Uri folderUri = new Uri(folder);
    return Uri.UnescapeDataString(folderUri.MakeRelativeUri(pathUri).ToString().Replace('/', Path.DirectorySeparatorChar));
}

How to get path relative to the working directory?

Give this a try.

@ECHO OFF
SETLOCAL EnableDelayedExpansion

for /r %%F in (*.txt) do (
    echo %%F|findstr /I /G:exclude.txt >nul 2>&1
    IF NOT "!ERRORLEVEL!"=="0" (
        REM do something here
    )
)

How to set relative path to current folder?

Just dot is working. The doctype makes a difference however as sometimes the ./ is fine as well.

<a href=".">Link to this folder</a>

Relative paths in Python

In the file that has the script, you want to do something like this:

import os
dirname = os.path.dirname(__file__)
filename = os.path.join(dirname, 'relative/path/to/file/you/want')

This will give you the absolute path to the file you're looking for. Note that if you're using setuptools, you should probably use its package resources API instead.

UPDATE: I'm responding to a comment here so I can paste a code sample. :-)

Am I correct in thinking that __file__ is not always available (e.g. when you run the file directly rather than importing it)?

I'm assuming you mean the __main__ script when you mention running the file directly. If so, that doesn't appear to be the case on my system (python 2.5.1 on OS X 10.5.7):

#foo.py
import os
print os.getcwd()
print __file__

#in the interactive interpreter
>>> import foo
/Users/jason
foo.py

#and finally, at the shell:
~ % python foo.py
/Users/jason
foo.py

However, I do know that there are some quirks with __file__ on C extensions. For example, I can do this on my Mac:

>>> import collections #note that collections is a C extension in Python 2.5
>>> collections.__file__
'/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/lib-
dynload/collections.so'

However, this raises an exception on my Windows machine.

Relative paths based on file location instead of current working directory

What you want to do is get the absolute path of the script (available via ${BASH_SOURCE[0]}) and then use this to get the parent directory and cd to it at the beginning of the script.

#!/bin/bash
parent_path=$( cd "$(dirname "${BASH_SOURCE[0]}")" ; pwd -P )

cd "$parent_path"
cat ../some.text

This will make your shell script work independent of where you invoke it from. Each time you run it, it will be as if you were running ./cat.sh inside dir.

Note that this script only works if you're invoking the script directly (i.e. not via a symlink), otherwise the finding the current location of the script gets a little more tricky)

Resolve relative path relative to another path instead of current working directory

why not just:

 path.resolve(__dirname, p)

__dirname works a bit differently and returns the current modules path, which can then be joined easily with the relative path.

How to get current relative directory of your Makefile?

The shell function.

You can use shell function: current_dir = $(shell pwd).
Or shell in combination with notdir, if you need not absolute path:
current_dir = $(notdir $(shell pwd)).

Update.

Given solution only works when you are running make from the Makefile's current directory.

As @Flimm noted:

Note that this returns the current working directory, not the parent directory of the Makefile.
For example, if you run cd /; make -f /home/username/project/Makefile, the current_dir variable will be /, not /home/username/project/.

Code below will work for Makefiles invoked from any directory:

mkfile_path := $(abspath $(lastword $(MAKEFILE_LIST)))
current_dir := $(notdir $(patsubst %/,%,$(dir $(mkfile_path))))

Get path of file relative to some directory in C#

I think you're looking for Path.GetRelativePath(...). Used like this:

string FileDirectory = "/tmp/simple";
string fullPath = "/tmp/simple/s1/s1.txt";

string result = Path.GetRelativePath(FileDirectory, fullPath);
// s1\s1.txt

To get the result with forward slash / instead, you can do a simple Replace() on the result:

result = result.Replace("\\", "/");
// s1/s1.txt

Reading file using relative path in python project

Relative paths are relative to current working directory.
If you do not your want your path to be, it must be absolute.

But there is an often used trick to build an absolute path from current script: use its __file__ special attribute:

from pathlib import Path

path = Path(__file__).parent / "../data/test.csv"
with path.open() as f:
    test = list(csv.reader(f))

This requires python 3.4+ (for the pathlib module).

If you still need to support older versions, you can get the same result with:

import csv
import os.path

my_path = os.path.abspath(os.path.dirname(__file__))
path = os.path.join(my_path, "../data/test.csv")
with open(path) as f:
    test = list(csv.reader(f))

[2020 edit: python3.4+ should now be the norm, so I moved the pathlib version inspired by jpyams' comment first]

---

Related Topics