Gdb - List Source of Current Function Without Typing Its Name

gdb - list source of current function without typing its name

(gdb) help list
List specified function or line.
With no argument, lists ten more lines after or around previous listing.
"list -" lists the ten lines before a previous ten-line listing.
One argument specifies a line, and ten lines are listed around that line.
Two arguments with comma between specify starting and ending lines to list.
Lines can be specified in these ways:
  LINENUM, to list around that line in current file,
  FILE:LINENUM, to list around that line in that file,
  FUNCTION, to list around beginning of that function,
  FILE:FUNCTION, to distinguish among like-named static functions.
  *ADDRESS, to list around the line containing that address.
With two args if one is empty it stands for ten lines away from the other arg.

The *ADDRESS is what is interesting.

On x86/x64 current pointer is in rip register so:

(gdb) list *$pc
0x7ffff7b018a0 is at ../sysdeps/unix/syscall-template.S:82.
77  in ../sysdeps/unix/syscall-template.S

The example is from cat command as I don't have anything with debug info at hand.

GNU gdb how to show source file name and lines of a symbol

Use info line command.

info line oyss_function

For example, assume the file test.c contains:

#include <stdio.h>

int main(void)
{
    printf("\n");
    return 0;
}

Then, invoking info line main in GDB gets:

(gdb) info line main
Line 4 of "test.c" starts at address 0x400498 <main> and ends at 0x40049c <main+4>.

Is there a quick way to display the source code at a breakpoint in gdb?

You can use the list command to show sources. list takes a "linespec", which is gdb terminology for the kinds of arguments accepted by break. So, you can either pass it whatever argument you used to make the breakpoint in the first place (e.g., list function) or you can pass it the file and line shown by info b (e.g., list mysource.c:75).

How to get GDB to show the source code while debugging?

gdb find . -type d | xargs printf " -d %s" prog
worked for me eventually. This supplies the directories recursively to gdb.
Found it here - https://titanwolf.org/Network/Articles/Article?AID=e61837e2-2ccc-4cce-80c8-3c8555aeacbd#gsc.tab=0

Now i am able to see the source code like how i wanted to :-)

Can I use gdb to skip a line without having to type line numbers?

jump +1

jumps to the next line line i.e. skipping the current line. You may also want to combine it with tbreak +1 to set a temporary breakpoint at the jump target.

See http://sourceware.org/gdb/current/onlinedocs/gdb/Specify-Location.html for more ways of expressing locations with gdb.

Note that without a breakpoint gdb is likely to continue execution normally instead of jumping. So if jumping doesn't seem to work, make sure you set a breakpoint at the destination.

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