can you have two conditions in an if statement
You can use logical operators
to combine your boolean expressions
.
&&
is a logical and (both conditions need to betrue
)||
is a logical or (at least one condition needs to betrue
)^
is a xor (exactly one condition needs to betrue
)- (
==
compares objects by identity)
For example:
if (firstCondition && (secondCondition || thirdCondition)) {
...
}
There are also bitwise operators:
&
is a bitwise and|
is a bitwise or^
is a xor
They are mainly used when operating with bits and bytes
. However there is another difference, let's take again a look at this expression:
firstCondition && (secondCondition || thirdCondition)
If you use the logical operators and firstCondition
evaluates to false
then Java
will not compute the second or third condition as the result of the whole logical expression is already known to be false
. However if you use the bitwise operators then Java
will not stop and continue computing everything:
firstCondition & (secondCondition | thirdCondition)
multiple conditions in same if statement in C
hi try this hope its work
#include<stdio.h>
#include<cono.h>
#include<iostream.h>
#include<stdlib.h>
void main(void)
{
int a,b;
printf("enter a");
scanf("%d",&a);
printf("enter b");
scanf("%d",&b);
if(a==1 && b<=8)
{
printf("you");
exit(0);
} else if(a==2 && 5<b && b<=10)
{
printf("you");
}
else{
printf("me");
}
getch();
}
Can you use 2 or more OR conditions in an if statement?
You need to code your tests differently:
if (number==1 || number==2 || number==3) {
cout << "Your number was 1, 2, or 3." << endl;
}
else if (number==4 || number==5 || number==6) {
cout << "Your number was 4, 5, or 6." << endl;
}
else {
cout << "Your number was above 6." << endl;
}
The way you were doing it, the first condition was being interpreted as if it were written like this
if ( (number == 1) || 2 || 3 ) {
The logical or operator (||
) is defined to evaluate to a true value if the left side is true or if the left side is false and the right side is true. Since 2
is a true value (as is 3
), the expression evaluates to true regardless of the value of number
.
Is better if statements with multiple conditions or more else if statements?
Let's make a simple experiment !
Dummy data
data <- data.frame(numerator = sample(c(0:9, NA), 10000, replace = T),
denominator = sample(c(0:9, NA), 10000, replace = T))
Two functions made up of two " if " conditions
f1 <- function(x){
num <- x[1] ; denom <- x[2]
if (is.na(num)){
result = 0
} else if (num == 0){
result = 0
} else if (is.na(denom)){
result = Inf
} else if (denom == 0){
result = Inf
} else {
result = num / denom
}
return(result)
}
f2 <- function(x){
num <- x[1] ; denom <- x[2]
if (is.na(num) || num == 0){
result = 0
} else if (is.na(denom) || denom == 0){
result = Inf
} else {
result = num / denom
}
return(result)
}
Benchmark analysis
library(microbenchmark)
library(ggplot2)
res <- microbenchmark(
type1 = {
quotient1 <- apply(data, 1, f1)
}, type2 = {
quotient2 <- apply(data, 1, f2)
}, times = 100
)
res
# Unit: milliseconds
# expr min lq mean median uq max
# type1 21.91925 23.70445 27.16314 25.52339 26.90110 122.91710
# type2 22.00139 23.64297 26.11080 25.04576 26.46136 42.62506
autoplot(res)
Conclusion
You can try the benchmark several times and you can find that
there is no significant difference between two if
conditions.
How to have multiple conditions for one if statement in python
I would use
def example(arg1, arg2, arg3):
if arg1 == 1 and arg2 == 2 and arg3 == 3:
print("Example Text")
The and
operator is identical to the logic gate with the same name; it will return 1 if and only if all of the inputs are 1. You can also use or
operator if you want that logic gate.
EDIT: Actually, the code provided in your post works fine with me. I don't see any problems with that. I think that this might be a problem with your Python, not the actual language.
What is better: multiple if statements or one if with multiple conditions?
One golden rule I follow is to "Avoid Nesting" as much as I can. But if it is at the cost of making my single if condition too complex, I don't mind nesting it out.
Besides you're using the short-circuit &&
operator. So if the boolean is false, it won't even try matching!
So,
if (boolean_condition && matcher.find(string)) {
...
}
is the way to go!
How to specify multiple conditions in an if statement in JavaScript
just add them within the main bracket of the if statement like
if ((Type == 2 && PageCount == 0) || (Type == 2 && PageCount == '')) {
PageCount= document.getElementById('<%=hfPageCount.ClientID %>').value;
}
Logically this can be rewritten in a better way too! This has exactly the same meaning
if (Type == 2 && (PageCount == 0 || PageCount == '')) {
If Statement with Multiple Conditions vs Individual If Statements
They are equivalent. The ||
operator short-circuits, so as soon as it reaches a condition that is true
, it stops checking other conditions and returns true
.
The |
operator does not short-circuit, so it would evaluate every operand before returning a value.
Same goes for &&
and &
but with false
. As soon as a false condition is reached, the &&
operator returns false.
So your two methods are functionally identical. Use whichever one you think is the cleanest, easiest to infer intent, etc.
Or does the compiler optimize the code to work most efficient no matter how the source is written?
Well, the optimizer can make changes to code for efficiency, but it cannot change the functional behavior, meaning it won't change the order of the operations. Imagine you had something like:
if ((x == 0) || (y/x > 1))
this is a common way to prevent divide-by-zero errors. If the compiler could rearrange the operands, then it could introduce divide-by-zero errors.
multiple conditions in while/if statement that runs if ANY of the conditions are true?
Yes, you can use the OR logic operator.
Example:
if(x==1 || x==2 || z==4)
{
//code
}
the code will be executed when atleast one of the conditions in the if statement is true
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