How to Add Border Around Linear Layout Except at the Bottom

How to add border around linear layout except at the bottom?

Create an XML file named border.xml in the drawable folder and put the following code in it.

 <?xml version="1.0" encoding="utf-8"?>
 <layer-list xmlns:android="http://schemas.android.com/apk/res/android">
  <item> 
    <shape android:shape="rectangle">
      <solid android:color="#FF0000" /> 
    </shape>
  </item>   
    <item android:left="5dp" android:right="5dp"  android:top="5dp" >  
     <shape android:shape="rectangle"> 
      <solid android:color="#000000" />
    </shape>
   </item>    
 </layer-list> 

Then add a background to your linear layout like this:

         android:background="@drawable/border"

EDIT :

This XML was tested with a galaxy s running GingerBread 2.3.3 and ran perfectly as shown in image below:

ALSO

tested with galaxy s 3 running JellyBean 4.1.2 and ran perfectly as shown in image below :

Finally its works perfectly with all APIs

EDIT 2 :

It can also be done using a stroke to keep the background as transparent while still keeping a border except at the bottom with the following code.

<?xml version="1.0" encoding="utf-8"?>
 <layer-list xmlns:android="http://schemas.android.com/apk/res/android">
   <item android:left="0dp" android:right="0dp"  android:top="0dp"  
        android:bottom="-10dp"> 
    <shape android:shape="rectangle">
     <stroke android:width="10dp" android:color="#B22222" />
    </shape>
   </item>  
 </layer-list> 

hope this help .

Add only top and bottom border on LinearLayout

Make this two file and put this code. you can set border top and bottom border,

main.xml

<TextView
      android:text="This is textline"
      android:background="@drawable/border_set"
/>

border_set.xml

This file located into full path project_root/res/drawable/border_set.xml

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
    <item>
      <shape 
        android:shape="rectangle">
            <stroke android:width="1dp" android:color="#FF000000" />
            <solid android:color="#FFDDDDDD" />

        </shape>
   </item>

   <item android:top="1dp" android:bottom="1dp"> 
      <shape 
        android:shape="rectangle">
            <stroke android:width="1dp" android:color="#000" />
            <solid android:color="#FFFFFF" />
        </shape>
   </item>

</layer-list>

How can I create a border around an Android LinearLayout?

Sure. You can add a border to any layout you want. Basically, you need to create a custom drawable and add it as a background to your layout. example:

Create a file called customborder.xml in your drawable folder:

<?xml version="1.0" encoding="UTF-8"?>
 <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle">
   <corners android:radius="20dp"/> 
   <padding android:left="10dp" android:right="10dp" android:top="10dp" android:bottom="10dp"/>
   <stroke android:width="1dp" android:color="#CCCCCC"/>
 </shape>

Now apply it as a background to your smaller layout:

<LinearLayout android:orientation="vertical"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:background="@drawable/customborder">

That should do the trick.

Also see:

• http://tekeye.biz/2012/add-a-border-to-an-android-layout
• How to add border around linear layout except at the bottom?

How to create a border around linear layout like the image below?

use this layout xml file

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#8106a9"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
tools:context=".MainActivity" >

<LinearLayout
    android:id="@+id/linearLayout1"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:layout_marginTop="10dp"
    android:background="@drawable/lin_bg"
    android:orientation="vertical" >
</LinearLayout>

<TextView
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignLeft="@+id/linearLayout1"
    android:layout_alignTop="@+id/linearLayout1"
    android:layout_marginLeft="28dp"
    android:layout_marginTop="-10dp"
    android:background="#8106a9"
    android:paddingLeft="5dp"
    android:paddingRight="5dp"
    android:text="Sim Card"
    android:textColor="@android:color/white" />

and lin_bg.xml

<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="rectangle" >

<stroke
    android:width="3dp"
    android:color="@android:color/white" />

then i get a layout like below

I hope this will help you

How to draw border on just one side of a linear layout?

You can use this to get border on one side

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
    <shape android:shape="rectangle">
        <solid android:color="#FF0000" />
    </shape>
</item>
<item android:left="5dp">
    <shape android:shape="rectangle">
        <solid android:color="#000000" />
    </shape>
</item>
</layer-list>

EDITED

As many including me wanted to have a one side border with transparent background, I have implemented a BorderDrawable which could give me borders with different size and color in the same way as we use css. But this could not be used via xml. For supporting XML, I have added a BorderFrameLayout in which your layout can be wrapped.

See my github for the complete source.

Android: how to draw a border to a LinearLayout

Do you really need to do that programmatically?

Just considering the title: You could use a ShapeDrawable as android:background…

For example, let's define res/drawable/my_custom_background.xml as:

<shape xmlns:android="http://schemas.android.com/apk/res/android"
       android:shape="rectangle">
  <corners
      android:radius="2dp"
      android:topRightRadius="0dp"
      android:bottomRightRadius="0dp"
      android:bottomLeftRadius="0dp" />
  <stroke
      android:width="1dp"
      android:color="@android:color/white" />
</shape>

and define android:background="@drawable/my_custom_background".

I've not tested but it should work.

Update:

I think that's better to leverage the xml shape drawable resource power if that fits your needs. With a "from scratch" project (for android-8), define res/layout/main.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:background="@drawable/border"
    android:padding="10dip" >
    <TextView
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:text="Hello World, SOnich"
        />
    [... more TextView ...]
    <TextView
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:text="Hello World, SOnich"
        />
</LinearLayout>

and a res/drawable/border.xml

<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
       android:shape="rectangle">
   <stroke
        android:width="5dip"
        android:color="@android:color/white" />
</shape>

Reported to work on a gingerbread device. Note that you'll need to relate android:padding of the LinearLayout to the android:width shape/stroke's value. Please, do not use @android:color/white in your final application but rather a project defined color.

You could apply android:background="@drawable/border" android:padding="10dip" to each of the LinearLayout from your provided sample.

As for your other posts related to display some circles as LinearLayout's background, I'm playing with Inset/Scale/Layer drawable resources (see Drawable Resources for further information) to get something working to display perfect circles in the background of a LinearLayout but failed at the moment…

Your problem resides clearly in the use of getBorder.set{Width,Height}(100);. Why do you do that in an onClick method?

I need further information to not miss the point: why do you do that programmatically? Do you need a dynamic behavior? Your input drawables are png or ShapeDrawable is acceptable? etc.

To be continued (maybe tomorrow and as soon as you provide more precisions on what you want to achieve)…

Round Border LinerLayout

1. Create a XML file named round_border in your layout folder.

2. Now put this code in your XML file :

   <shape xmlns:android="http://schemas.android.com/apk/res/android"> 
   <stroke android:width="4dp" android:color="#FF00FF00" /> 
   <solid android:color="#ffffff" /> 
   <padding android:left="7dp" android:top="7dp" 
           android:right="7dp" android:bottom="7dp" /> 
   <corners android:radius="10dp" /> 
   

3. Now use this file as a background of your LinearLayout like this :

   <LinearLayout android:id="@+id/LinearLayout01"
   android:layout_width="fill_parent"
   android:layout_height="fill_parent"
   android:orientation="vertical"
   android:padding="20dip"
   android:background="@drawable/round_border">
   

Is there an easy way to add a border to the top and bottom of an Android View?

In android 2.2 you could do the following.

Create an xml drawable such as /res/drawable/textlines.xml and assign this as a TextView's background property.

<TextView
android:text="My text with lines above and below"
android:background="@drawable/textlines"
/>

/res/drawable/textlines.xml

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
    <item>
      <shape 
        android:shape="rectangle">
            <stroke android:width="1dp" android:color="#FF000000" />
            <solid android:color="#FFDDDDDD" />

        </shape>
   </item>

   <item android:top="1dp" android:bottom="1dp"> 
      <shape 
        android:shape="rectangle">
            <stroke android:width="1dp" android:color="#FFDDDDDD" />
            <solid android:color="#00000000" />
        </shape>
   </item>

</layer-list>

The down side to this is that you have to specify an opaque background colour, as transparencies won't work. (At least i thought they did but i was mistaken). In the above example you can see that the solid colour of the first shape #FFdddddd is copied in the 2nd shapes stroke colour.

---

Related Topics