getSize() giving me errors
This supports both older and newer devices:
private static Point getDisplaySize(final Display display) {
final Point point = new Point();
try {
display.getSize(point);
} catch (java.lang.NoSuchMethodError ignore) { // Older device
point.x = display.getWidth();
point.y = display.getHeight();
}
return point;
}
Why os.path.getsize() throw error in python?
Try this:
printSize(os.path.abspath(os.path.join(folderName, filename)))
SplFileInfo::getSize(): stat failed
The error occured because you have move()d the file and then getSize()d the object. Try to set a variable and assign the size and then move the file.
{
...
$size=$request->file('img')->getSize();
$request->file('img')->move(public_path('storage/services/'), $imageName);
}
PIL Internal Exception: {TypeError}getsize() takes exactly 1 argument (3 given)
Change below
font = ImageFont.load_default().font
to
font = ImageFont.load_default()
And it should work
os.path.getsize() is not giving the true size of the file on OSX
This is because you're asking for the size of the directory itself, not the size of its contents. A directory in Unix (OSX) is considered to be a special file that contains meta data; Information that describes the directory on the file system. what .getsize()
is telling you is that the meta data only occupies 510 bytes.
Notice the first example your book gives is asking for the size of a file called calc.exe
, not a directory.
To get the total size of the contents of a directory, you need to recursively walk the entire hierarchy and call getsize()
on every file. Here is a one line solution to do this:
sum([os.path.getsize(f) for f in os.listdir('.') if os.path.isfile(f)])
Where '.'
is the base path for the directory you're trying to get the size of.
can't get a file size in python
It is failing because of the line os.chdir(mypath)
. You don't need to chdir()
.
Assuming the path is correct and the file exists, it should work (print the file size) if you remove the os.chdir()
statement.
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