Number of Words in a Swift String For Word Count Calculation

Number of words in a Swift String for word count calculation

update: Xcode 10.2.x • Swift 5 or later

Using Foundation method enumerateSubstrings(in: Range)and setting .byWords as options:

let sentence = "I want to an algorithm that could help find out how many words are there in a string separated by space or comma or some character. And then append each word separated by a character to an array which could be added up later I'm making an average calculator so I want the total count of data and then add up all the words. By words I mean the numbers separated by a character, preferably space Thanks in advance"

var words: [Substring] = []
sentence.enumerateSubstrings(in: sentence.startIndex..., options: .byWords) { _, range, _, _ in
    words.append(sentence[range])
}
print(words) // "["I", "want", "to", "an", "algorithm", "that", "could", "help", "find", "out", "how", "many", "words", "are", "there", "in", "a", "string", "separated", "by", "space", "or", "comma", "or", "some", "character", "And", "then", "append", "each", "word", "separated", "by", "a", "character", "to", "an", "array", "which", "could", "be", "added", "up", "later", "I\\'m", "making", "an", "average", "calculator", "so", "I", "want", "the", "total", "count", "of", "data", "and", "then", "add", "up", "all", "the", "words", "By", "words", "I", "mean", "the", "numbers", "separated", "by", "a", "character", "preferably", "space", "Thanks", "in", "advance"]\n"
print(words.count)  // 79

Or using native Swift 5 new Character property isLetter and the split method:

let words =  sentence.split { !$0.isLetter }

print(words) // "["I", "want", "to", "an", "algorithm", "that", "could", "help", "find", "out", "how", "many", "words", "are", "there", "in", "a", "string", "separated", "by", "space", "or", "comma", "or", "some", "character", "And", "then", "append", "each", "word", "separated", "by", "a", "character", "to", "an", "array", "which", "could", "be", "added", "up", "later", "I", "m", "making", "an", "average", "calculator", "so", "I", "want", "the", "total", "count", "of", "data", "and", "then", "add", "up", "all", "the", "words", "By", "words", "I", "mean", "the", "numbers", "separated", "by", "a", "character", "preferably", "space", "Thanks", "in", "advance"]\n"

print(words.count)  // 80

---

Extending StringProtocol to support Substrings as well:

extension StringProtocol {
    var words: [SubSequence] { 
        return split { !$0.isLetter } 
    }
    var byWords: [SubSequence] {
        var byWords: [SubSequence] = []
        enumerateSubstrings(in: startIndex..., options: .byWords) { _, range, _, _ in
            byWords.append(self[range])
        }
        return byWords
    }
}

---

sentence.words  // ["I", "want", "to", "an", "algorithm", "that", "could", "help", "find", "out", "how", "many", "words", "are", "there", "in", "a", "string", "separated", "by", "space", "or", "comma", "or", "some", "character", "And", "then", "append", "each", "word", "separated", "by", "a", "character", "to", "an", "array", "which", "could", "be", "added", "up", "later", "I", "m", "making", "an", "average", "calculator", "so", "I", "want", "the", "total", "count", "of", "data", "and", "then", "add", "up", "all", "the", "words", "By", "words", "I", "mean", "the", "numbers", "separated", "by", "a", "character", "preferably", "space", "Thanks", "in", "advance"]

How to get the number of real words in a text in Swift

Consecutive spaces and newlines aren't coalesced into one generic whitespace region, so you're simply getting a bunch of empty "words" between successive whitespace characters. Get rid of this by filtering out empty strings:

let components = str.components(separatedBy: .whitespacesAndNewlines)
let words = components.filter { !$0.isEmpty }

print(words.count)  // 17

The above will print 17 because you haven't included , as a separation character, so the string "planners,are" is treated as one word.

You can break that string up as well by adding punctuation characters to the set of separators like so:

let chararacterSet = CharacterSet.whitespacesAndNewlines.union(.punctuationCharacters)
let components = str.components(separatedBy: chararacterSet)
let words = components.filter { !$0.isEmpty }

print(words.count)  // 18

Now you'll see a count of 18 like you expect.

Word Count in Swift

Your method was pretty solid, but this makes a couple improvements. I store the value count using Swifts "if let" keyword to check for an optional value. Then I can use count when updating the dictionary. I used the shorthand notation for updateValue (dict[key] = val). I also split the original string on all whitespace instead of just a single space.

func wordCount(s: String) -> Dictionary<String, Int> {
    var words = s.componentsSeparatedByCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
    var wordDictionary = Dictionary<String, Int>()
    for word in words {
        if let count = wordDictionary[word] {
            wordDictionary[word] = count + 1
        } else {
            wordDictionary[word] = 1
        }
    }
    return wordDictionary
}

Swift 4 iOS - Word Count from UITextField

That's because your textview has no text in it at that point.

Try this:

INPUT.text = "Some Text"

Do get the text from an actual input:

INPUT.addTarget(self, action: #selector(textFieldDidChange(_:)), for: .editingChanged)

func textFieldDidChange(_ textField: UITextField) {

    let strings : String! = INPUT.text
    let spaces = CharacterSet.whitespacesAndNewlines.union(.punctuationCharacters)
    let words = strings.components(separatedBy: spaces)
    print(words.count)

}

Calculating word count from a url in swift

First of all, you need to parse the HTML. HTML can only be parsed reliably with dedicated HTML parser. Please don't use Regular Expressions or any other search method to parse HTML. You may read it why from this link. If you are using swift, you may try Fuzi or Kanna. After you get the body text with any one of the library, you have to remove extra white spaces and count the words. I have written some basic code with Fuzi library for you to get started.

import Fuzi

// Trim
func trim(src:String) -> String {
    return src.trimmingCharacters(in: CharacterSet.whitespacesAndNewlines)
}

// Remove Extra double spaces and new lines
func clean(src:String) ->String {
    return src.replacingOccurrences(
        of: "\\s+",
        with: " ",
        options: .regularExpression)
}


let htmlUrl = URL(fileURLWithPath: ((#file as NSString).deletingLastPathComponent as NSString).appendingPathComponent("test.html"))
do {
    let data = try Data(contentsOf: htmlUrl)
    let document = try HTMLDocument(data: data)
    // get body of text
    if let body = document.xpath("//body").first?.stringValue {
        let cleanBody = clean(src: body)
        let trimmedBody = trim(src:cleanBody)
        print(trimmedBody.components(separatedBy: " ").count)
    }
} catch {
    print(error)
}

If you are fancy, you may change my global functions to String extension or you can combine them in a single function. I wrote it for clarity.

How can I count the number of sentences in a given text in Swift?

Just add the character in charset by which you are going to differentiate your sentences:

I am assuming ? . , for now:

    let input = "That would be the text. it hast 3? periods."
    let charset = CharacterSet(charactersIn: ".?,")
    let arr = input.components(separatedBy: charset)
    let count = arr.count - 1

Here arr would be:

["That would be the text", " it hast 3", " periods", ""]

decrease count by 1, to get actual sentences.

Note: If you don't want to consider " , " then remove it from charset.

---

Related Topics